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<record version="14" id="6596">
 <title>Krull valuation</title>
 <name>KrullValuation</name>
 <created>2004-12-27 14:20:41</created>
 <modified>2007-04-05 06:33:12</modified>
 <type>Definition</type>
<parent id="2835">valuation</parent>
 <creator id="2872" name="pahio"/>
 <author id="2872" name="pahio"/>
 <classification>
	<category scheme="msc" code="11R99"/>
	<category scheme="msc" code="12J20"/>
	<category scheme="msc" code="13A18"/>
	<category scheme="msc" code="13F30"/>
 </classification>
 <defines>
	<concept>value group</concept>
	<concept>rank of Krull valuation</concept>
	<concept>rank of valuation</concept>
 </defines>
 <related>
	<object name="OrderedGroup"/>
	<object name="TrivialValuation"/>
	<object name="IsolatedSubgroup"/>
	<object name="ValueGroupOfCompletion"/>
	<object name="PlaceOfField"/>
	<object name="OrderValuation"/>
	<object name="AlternativeDefinitionOfValuation2"/>
	<object name="UniquenessOfDivisionAlgorithmInEuclideanDomain"/>
 </related>
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 <content>\textbf{Definition.}\, The mapping\, $|.|\!:\, K\to G$,\, where $K$ is a field and $G$ an ordered group equipped with zero, is a {\em Krull valuation} of $K$, if it has the properties
\begin{enumerate}
 \item $|x| = 0 \,\,\Leftrightarrow\,\, x = 0$;
 \item $|xy| = |x|\cdot|y|$;
 \item $|x+y| \leqq \max\{|x|,\,|y|\}$.
\end{enumerate}

Thus the Krull valuation is more general than the usual \PMlinkname{valuation}{Valuation}, which is also characterized as \PMlinkescapetext{{\em valuation of rank 1}} and which has real values.\, The image\, $|K\!\smallsetminus\!\{0\}|$\, is called the {\em value group} of the Krull valuation; it is abelian.\, In general, the {\em rank of Krull valuation} \PMlinkescapetext{means} the \PMlinkname{rank}{IsolatedSubgroup} of the value group.

We may say that a Krull valuation is \PMlinkname{non-archimedean}{Valuation}.

\subsection*{Some values}
\begin{itemize}
 \item $|1| = 1$\,\, because the Krull valuation is a group homomorphism from the multiplicative group of $K$ to the ordered group.
 \item $|-1| = 1$\,\, because\, $1 = |(-1)^2| = |-1|^2$\,\, and 1 is the only element of the ordered group being its own inverse ($S\cap S^{-1} = \varnothing$).
 \item $|-x| = |(-1)x| = |-1|\cdot|x| = |x|$
\end{itemize}

\begin{thebibliography}{9}
\bibitem{Artin} {\sc Emil Artin}: {\em Theory of Algebraic Numbers}.\, Lecture notes.\, Mathematisches Institut, G\"ottingen (1959).
\end{thebibliography}
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