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<record version="1" id="6734">
 <title>limit comparison test</title>
 <name>LimitComparisonTest</name>
 <created>2005-02-10 07:44:58</created>
 <modified>2005-02-10 07:44:58</modified>
 <type>Theorem</type>
 <creator id="2414" name="alozano"/>
 <author id="2414" name="alozano"/>
 <classification>
	<category scheme="msc" code="40-00"/>
 </classification>
 <related>
	<object name="DeterminingSeriesConvergence"/>
	<object name="SequenceDeterminingConvergenceOfSeries"/>
 </related>
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 <content>The following theorem is a powerful test for convergence of series.

\begin{thm}[Limit \PMlinkescapetext{Comparison Test}] Let $\sum_{n=0}^\infty a_n$ and
$\sum_{n=0}^\infty b_n$ be two series of positive numbers. \\
\begin{enumerate}
\item If the limit $$\lim_{n\to \infty} \frac{a_n}{b_n}=L$$ exists and $L\neq 0$ is a
non-zero finite number, then both series $\sum_{n=0}^\infty a_n$ and
$\sum_{n=0}^\infty b_n$ converge or both diverge.\\
\item If $L=0$ and $\sum_{n=0}^\infty b_n$ converges then $\sum_{n=0}^\infty a_n$ converges as well. If $L=0$ and $\sum_{n=0}^\infty a_n$ diverges then $\sum_{n=0}^\infty b_n$ diverges as well.\\
\item Similarly, if the limit is infinite (``$L=\infty$'') and  $\sum_{n=0}^\infty a_n$ converges then $\sum_{n=0}^\infty b_n$ converges as well. If $L=\infty$ and $\sum_{n=0}^\infty b_n$ diverges then $\sum_{n=0}^\infty a_n$ diverges as well.
\end{enumerate}
\end{thm}</content>
</record>
