<?xml version="1.0" encoding="UTF-8"?>

<record version="2" id="6824">
 <title>root-discriminant</title>
 <name>RootDiscriminant</name>
 <created>2005-02-24 16:34:57</created>
 <modified>2005-02-24 16:37:42</modified>
 <type>Definition</type>
<parent id="2895">discriminant</parent>
 <creator id="2414" name="alozano"/>
 <author id="2414" name="alozano"/>
 <classification>
	<category scheme="msc" code="11R29"/>
 </classification>
 <synonyms>
	<synonym concept="root-discriminant" alias="root discriminant"/>
 </synonyms>
 <related>
	<object name="ExistenceOfHilbertClassField"/>
 </related>
 <keywords>
	<term>discriminant</term>
	<term>root discriminant</term>
 </keywords>
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 <content>\begin{defn}
Let $K$ be a number field, let $d_K$ be its discriminant and let $n=[K:\Rats]$ be the degree over $\Rats$. The quantity:
$$|\sqrt[n]{d_K}|$$
is called the {\bf root-discriminant} of $K$ and it is usually denoted by $\operatorname{rd}_K$.
\end{defn}

The following lemma is one of the motivations for the previous definition:

\begin{lemma}
Let $E/F$ be an extension of number fields which is unramified at all finite primes. Then $\rd_E=\rd_F$. In particular, the Hilbert class field of a number field has the same root-discriminant as the number field.
\end{lemma}

\begin{proof}
Notice that the relative discriminant ideal (or different) for $E/F$ is the ring of integers in $F$. Therefore we have:
$$|d_E|=|d_F|^{[E:F]}$$
The results follows by taking $[E:\Rats]$-th roots on both sides of the previous equation.
\end{proof}</content>
</record>
