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<record version="2" id="6842">
 <title>the ramification index and the inertial degree are multiplicative in towers</title>
 <name>RamificationIndexAndTheInertialDegreeAreMultiplicativeInTowers</name>
 <created>2005-03-03 17:19:45</created>
 <modified>2005-03-03 17:22:04</modified>
 <type>Theorem</type>
<parent id="6818">splitting and ramification in number fields and Galois extensions</parent>
 <creator id="2414" name="alozano"/>
 <author id="2414" name="alozano"/>
 <classification>
	<category scheme="msc" code="11S15"/>
	<category scheme="msc" code="13B02"/>
	<category scheme="msc" code="12F99"/>
 </classification>
 <related>
	<object name="Ramify"/>
	<object name="InertialDegree"/>
 </related>
 <keywords>
	<term>towers of number fields</term>
	<term>ramification</term>
	<term>inertia</term>
 </keywords>
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%\usepackage{psfrag}
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\newtheorem{defn}{Definition}
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\newcommand{\Nats}{\mathbb{N}}
\newcommand{\Ints}{\mathbb{Z}}
\newcommand{\Reals}{\mathbb{R}}
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\newcommand{\p}{{\mathfrak{p}}}
\newcommand{\A}{{\mathfrak{A}}}
\renewcommand{\P}{{\mathfrak{P}}}
\newcommand{\Pcal}{\mathcal{P}}
\newcommand{\Gal}{\operatorname{Gal}}
\newcommand{\intK}{\mathcal{O}_K}
\newcommand{\intF}{\mathcal{O}_F}
\newcommand{\intE}{\mathcal{O}_E}</preamble>
 <content>\begin{thm}
Let $E,\ F$ and $K$ be number fields in a tower:
$$K\subseteq F \subseteq E$$
and let $\intE,\ \intF$ and $\intK$ be their rings of integers respectively. Suppose $\p$ is a prime ideal of $\intK$ and let $\P$ be a prime ideal of $\intF$ lying above $\p$, and $\Pcal$ is a prime ideal of $\intE$ lying above $\P$. 

\begin{center}
$\xymatrix{
{E} \ar@{-}[d] &amp; {\intE} \ar@{-}[d] &amp; {\Pcal} \ar@{-}[d] \\
{F} \ar@{-}[d] &amp; {\intF} \ar@{-}[d] &amp; {\P} \ar@{-}[d]\\
K &amp; \intK &amp; \p }$
\end{center}

Then the indices of the extensions, the ramification indices and inertial degrees satisfy:
\begin{eqnarray}
[E:K] &amp;=&amp; [E:F]\cdot [F:K],\\
\nonumber &amp; &amp;\\
e(\Pcal|\p) &amp;=&amp; e(\Pcal|\P)\cdot e(\P|\p),\\
\nonumber &amp; &amp;\\
f(\Pcal|\p) &amp;=&amp; f(\Pcal|\P)\cdot f(\P|\p).
\end{eqnarray}
\end{thm}</content>
</record>
