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<record version="9" id="7219">
 <title>ideal decomposition in Dedekind domain</title>
 <name>IdealDecompositionInDedekindDomain</name>
 <created>2005-07-12 06:11:10</created>
 <modified>2008-12-06 17:55:12</modified>
 <type>Topic</type>
<parent id="2854">Dedekind domain</parent>
 <creator id="2872" name="pahio"/>
 <author id="2872" name="pahio"/>
 <classification>
	<category scheme="msc" code="11R04"/>
	<category scheme="msc" code="11R37"/>
 </classification>
 <related>
	<object name="ProductOfFinitelyGeneratedIdeals"/>
	<object name="PolynomialCongruence"/>
	<object name="CancellationIdeal"/>
	<object name="DivisibilityInRings"/>
	<object name="IdealsOfADiscreteValuationRingArePowersOfItsMaximalIdeal"/>
	<object name="DivisorTheory"/>
 </related>
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 <content>According to the entry ``\PMlinkname{fractional ideal}{FractionalIdeal}'', we can \PMlinkescapetext{state} that in a Dedekind domain $R$, each non-zero integral ideal $\mathfrak{a}$ may be written as a product of finitely many prime ideals $\mathfrak{p}_i$ of $R$, 
 $$\mathfrak{a} = \mathfrak{p}_1\mathfrak{p}_2...\mathfrak{p}_k.$$
The \PMlinkescapetext{product decomposition is unique up to the order of the factors}.\, This is stated and proved, with more general assumptions, in the entry ``\PMlinkname{prime ideal factorisation is unique}{PrimeIdealFactorizationIsUnique}''.\\

\textbf{Corollary.}\, If $\alpha_1$, $\alpha_2$, ..., $\alpha_m$ are elements of a Dedekind domain $R$ and $n$ is a positive integer, then one has
\begin{align}
  (\alpha_1,\,\alpha_2,\,...,\,\alpha_m)^n = 
  (\alpha_1^n,\,\alpha_2^n,\,...,\,\alpha_m^n)
\end{align}
for the ideals of $R$.\\

This corollary may be proven by induction on the number $m$ of the \PMlinkescapetext{generators (not on the exponent} $n$).</content>
</record>
