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<record version="4" id="7458">
 <title>scaling of the open ball in a normed vector space</title>
 <name>ScalingOfTheOpenBallInANormedVectorSpace</name>
 <created>2005-10-29 13:56:35</created>
 <modified>2009-04-19 18:21:50</modified>
 <type>Theorem</type>
<parent id="1604">normed vector space</parent>
 <creator id="1858" name="matte"/>
 <author id="3771" name="CWoo"/>
 <author id="409" name="mps"/>
 <author id="1858" name="matte"/>
 <classification>
	<category scheme="msc" code="46B99"/>
 </classification>
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 <content>% This is written from scratch with no reference

Let $V$ be a vector space over a field $F$ (real or complex), and let 
$\Vert\cdot \Vert$ be a norm on $V$. Further, 
for $r&gt;0$, $v\in V$, let
$$
 B_r(v) = \{ w\in V: \Vert w-v\Vert &lt; r \}.
$$
Then for any non-zero $\lambda\in F$, we have 
$$
  \lambda B_r(v) = B_{|\lambda| r}(\lambda v).
$$

The claim is clear for $\lambda =0$, so we can assume that $\lambda \neq 0$. 
Then
\begin{eqnarray*}
\lambda B_r(v) &amp;=&amp;  \{ z\in V: \Vert w-v\Vert &lt; r\ \mbox{and}\ z=\lambda w \} \\
               &amp;=&amp;  \{ z\in V: \Vert \frac{z}{\lambda}-v\Vert &lt; r \} \\
               &amp;=&amp;  \{ z\in V: \Vert z-\lambda v\Vert &lt; |\lambda| r \} \\
               &amp;=&amp;  B_{|\lambda| r}(\lambda v).
\end{eqnarray*}</content>
</record>
