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<record version="3" id="7519">
 <title>all norms are not equivalent</title>
 <name>AllNormsAreNotEquivalent</name>
 <created>2005-12-06 04:37:48</created>
 <modified>2006-07-29 08:36:43</modified>
 <type>Example</type>
<parent id="4312">equivalent norms</parent>
 <creator id="1858" name="matte"/>
 <author id="13753" name="Mathprof"/>
 <author id="1858" name="matte"/>
 <classification>
	<category scheme="msc" code="46B99"/>
 </classification>
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% of TeX increases, you will probably want to edit this, but
% it should be fine as is for beginners.

% almost certainly you want these
\usepackage{amssymb}
\usepackage{amsmath}
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 \usepackage{bbm}
 \newcommand{\Z}{\mathbbmss{Z}}
 \newcommand{\C}{\mathbbmss{C}}
 \newcommand{\F}{\mathbbmss{F}}
 \newcommand{\R}{\mathbbmss{R}}
 \newcommand{\Q}{\mathbbmss{Q}}



\newcommand*{\norm}[1]{\lVert #1 \rVert}
\newcommand*{\abs}[1]{| #1 |}



\newtheorem{thm}{Theorem}
\newtheorem{defn}{Definition}
\newtheorem{prop}{Proposition}
\newtheorem{lemma}{Lemma}
\newtheorem{cor}{Corollary}</preamble>
 <content>Let $V$ be the vector space of continuous 
functions $[-1,1]\to \R$ that are differentiable at $0$. 
Then we can define norms
$$
\Vert f \Vert = \max_{x\in [-1,1]} |f|,
$$
and 
$$
\Vert f \Vert' = \Vert f \Vert+|f'(0)|.
$$
It is not difficult to find a sequence of functions $f_1, f_2, \ldots$
in $V$ such that 
\begin{enumerate}
\item $f_k'(0)=k$ for $k=1,2,\ldots$, 
\item $\Vert f_k\Vert = 1$.
\end{enumerate}
Then $\Vert f_k \Vert = 1$, and $\Vert f_k \Vert'=1+k$, so there is no
$C&gt;1$ such that 
$$
   \Vert f \Vert' \le C \Vert f \Vert \quad f\in V,
$$
and $\Vert\cdot \Vert$ and $\Vert\cdot \Vert'$
cannot be \PMlinkescapetext{equivalent}.</content>
</record>
