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<record version="4" id="7689">
 <title>easy calculation of the area of an ellipse</title>
 <name>EasyCalculationOfTheAreaOfAnEllipse</name>
 <created>2006-03-06 16:31:06</created>
 <modified>2007-04-22 11:30:26</modified>
 <type>Definition</type>
<parent id="7102">ellipse</parent>
 <creator id="11260" name="cvalente"/>
 <author id="13753" name="Mathprof"/>
 <author id="1863" name="Wkbj79"/>
 <author id="11260" name="cvalente"/>
 <classification>
	<category scheme="msc" code="53A04"/>
 </classification>
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 <content>Consider the unit circle $\left \{ \right (x,y) \in \mathbb{R}^2 : x^2+y^2\le 1\}$. It's a well known fact that the area of this set is $\pi$.

Now consider the following linear transformation $(x,y)\to(u,v)=(ax,by)$.

The determinant of the transformation is $ab$ and the transformed circle is:

 $\left \{ \right (u,v) \in \mathbb{R}^2 : \left (\frac{u}{a} \right )^2 + \left (\frac{v}{b} \right )^2 \le 1\}$  an ellipse of axis $(a,b)$.

Now since the Jacobian of the transformation is constant, the \PMlinkname{change of variables in integral theorem}{ChangeOfVariablesInIntegralOnMathbbRn} allows us to say the area of the transformed set is $ab$ 
times the area of the original set.

Thus, the area of an ellipse is $\pi a b$.</content>
</record>
