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<record version="8" id="7701">
 <title>lattice interval</title>
 <name>LatticeInterval</name>
 <created>2006-03-08 12:52:49</created>
 <modified>2007-05-23 08:29:56</modified>
 <type>Definition</type>
 <creator id="3771" name="CWoo"/>
 <author id="3771" name="CWoo"/>
 <classification>
	<category scheme="msc" code="06B99"/>
	<category scheme="msc" code="06A06"/>
 </classification>
 <defines>
	<concept>prime interval</concept>
	<concept>poset interval</concept>
	<concept>locally finite lattice</concept>
 </defines>
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 <content>\textbf{Definition}.  Let $L$ be a lattice.  A subset $I$ of $L$ is called a \emph{lattice interval}, or simply an \emph{\PMlinkescapetext{interval}} if there exist elements $a,b\in L$ such that $$I=\lbrace t\in L\mid a\le t\le b\rbrace:=[a,b].$$

The elements $a,b$ are called the endpoints of $I$.  Clearly $a,b\in I$.  Also, the endpoints of a lattice interval are unique: if $[a,b]=[c,d]$, then $a=c$ and $b=d$.

\textbf{Remarks}.
\begin{itemize}
\item It is easy to see that the name is derived from that of an interval on a number line.  From this analogy, one can easily define lattice intervals without one or both endpoints.  Whereas an interval on a number line is linearly ordered, a lattice interval in general is not.  Nevertheless, a lattice interval $I$ of a lattice $L$ is a sublattice of $L$.
\item A bounded lattice is itself a lattice interval: $[0,1]$.
\item A \emph{prime interval} is a lattice interval that contains its endpoints and nothing else.  In other words, if $[a,b]$ is prime, then any $c\in [a,b]$ implies that either $c=a$ or $c=b$.  Simply put, $b$ covers $a$.  If a lattice $L$ contains $0$, then for any $a\in L$, $[0,a]$ is a prime interval iff $a$ is an atom.
\item Since no operations of meet and join are used, all of the above discussion can be generalized to define an interval in a poset.
\item Given a lattice $L$, let $\mathcal{B}$ be the collection of all lattice intervals without endpoints, we can form a topolgy on $L$ with $\mathcal{B}$ as the subbasis.  This does not insure that $\wedge$ and $\vee$ are continuous, so that $L$ with this topological structure may not be a topological lattice.
\item \textbf{Locally Finite Lattice}.  A lattice that is derived based on the concept of lattice interval is that of a locally finite lattice.  A lattice $L$ is locally finite iff every one of its interval is finite.  Unless the lattice is finite, a locally finite lattice, if infinite, is either topless or bottomless.
\end{itemize}</content>
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