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<record version="6" id="7913">
 <title>preadditive category</title>
 <name>PreadditiveCategory</name>
 <created>2006-05-16 13:12:32</created>
 <modified>2006-05-23 21:23:25</modified>
 <type>Definition</type>
 <creator id="3771" name="CWoo"/>
 <author id="3771" name="CWoo"/>
 <classification>
	<category scheme="msc" code="18E05"/>
 </classification>
 <defines>
	<concept>ab-category</concept>
 </defines>
 <related>
	<object name="AdditiveCategory"/>
	<object name="PreAdditiveFunctors"/>
	<object name="CategoryOfAdditiveFractions"/>
 </related>
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 <content>\subsection{Ab-Category}
A category $\mathcal{C}$ is an \emph{ab-category} or \emph{\textbf{ab}-category} if
\begin{enumerate}
\item for every pair of objects $A,B$ of $\mathcal{C}$, there is a binary operation called addition, written $+_{(A,B)}$ or simply $+$, defined on $\operatorname{hom}(A,B)$,
\item the set $\hom(A,B)$, together with $+$ is an abelian group, 
\item (left distributivity) if $f,g\in \hom(A,B)$ and $h\in 
\hom(B,C)$, then $h(f+g)=hf+hg$,
\item (right distributivity) if $f,g\in \hom(A,B)$ and $h\in 
\hom(C,A)$, then $(f+g)h=fh+gh$.
\end{enumerate}
In a nutshell, an \emph{ab-category} is a category in which every hom set in $\mathcal{C}$ is an abelian group such that morphism composition distributes over addition.  Ab in the name stands for abelian, clearly indicative of the second condition above.  

Since a group has a multiplicative (or additive if abelian) identity, $\hom(A,B)\neq\varnothing$ for every pair of objects $A,B$ in $\mathcal{C}$.  Furthermore, each $\hom(A,B)$ contains a unique morphism, written $0_{(A,B)}$, as the additive identity of $\hom(A,B)$.  Because the subset 
$$\lbrace f\cdot 0_{(A,B)}\mid f\in\hom(B,C)\rbrace$$
of $\hom(A,C)$ is also a subgroup by right distributivity, and the additive identity of a subgroup coincides with the additive identity of the group, we have the following identity $$0_{(B,C)}0_{(A,B)}=0_{(A,C)}.$$

There are many examples of ab-categories, including the category of abelian groups, the category of $R$-modules ($R$ a ring), the category of chain complexes, and the category of rings (not necessarily containing a multiplicative identity).  However, the category of rings with 1 is not an ab-category (see below for more detail).  Nevertheless, a unital ring $R$ itself considered as a category is an ab-category, as the ring of endomorphisms clearly forms an abelian group.  It is in fact a ring!  This can be seen as a special case of the fact that, in an ab-category, $\operatorname{End}(A)=\hom(A,A)$ is always a ring (with 1).  So, conversely, an ab-category with one object is a ring with 1, whose morphisms are elements of the ring.

\subsection{Preadditive Category}
If an ab-category has an initial object, that object is also a terminal object.  By duality, the converse is also true.  Therefore, in an ab-category, initial object, terminal object, and zero object are synonymous.  In the category $\mathcal{R}$ of unital rings, $\mathbb{Z}$ is an initial object, but it has no terminal object, therefore $\mathcal{R}$ is not an ab-category.

An ab-category with a zero object $O$ is called a \emph{preadditive category}.

In a preadditive category, the groups $\hom(A,O)$ and $\hom(O,B)$ are trivial groups by the definition of the zero object $O$.  Therefore, the zero morphism in $\hom(A,B)$ is also the additive identity of $\hom(A,B)$:
$$0_{(A,B)}=0_{(O,B)}0_{(A,O)}=A\longrightarrow O\longrightarrow B.$$

Most of the examples of ab-categories are readily seen to be preadditive.  If a preadditive category $R$ has only one object, we see from above that it must be a ring.  But this object must also be a zero object, so that $\operatorname{End}(R)$ must be trivial, which means $R$ itself must be trivial too, $R=0$!

\textbf{Remark}.  In some literature, a preadditive category is an ab-category, and some do not insist that a preadditive category contains a zero object.  Here, we choose to differentiate the two.</content>
</record>
