exactly dividesExactlyDivides2006-08-20 00:37:562006-08-20 00:38:39Definition\usepackage{amssymb}
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Let $p$ be a prime, $m$ be a positive integer, and $n$ be an integer. Then $p^m$ \emph{exactly divides} $n$ (denoted as $p^m \Vert n$) if $p^m$ divides $n$ and $p^{m+1}$ does not divide $n$.