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 <title>type of a distribution function</title>
 <name>TypeOfADistributionFunction</name>
 <created>2006-11-22 22:50:34</created>
 <modified>2006-11-29 23:39:20</modified>
 <type>Definition</type>
<parent id="3451">distribution function</parent>
 <creator id="3771" name="CWoo"/>
 <author id="3771" name="CWoo"/>
 <classification>
	<category scheme="msc" code="60E05"/>
	<category scheme="msc" code="62E10"/>
 </classification>
 <defines>
	<concept>type</concept>
	<concept>scale factor</concept>
	<concept>location factor</concept>
	<concept>standard distribution function</concept>
	<concept>location family</concept>
	<concept>scale family</concept>
 </defines>
 <synonyms>
	<synonym concept="type of a distribution function" alias="centering factor"/>
	<synonym concept="type of a distribution function" alias="scale parameter"/>
	<synonym concept="type of a distribution function" alias="location parameter"/>
 </synonyms>
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 <content>Two distribution functions $F,G:\mathbb{R}\to [0,1]$ are said to of the same \emph{type} if there exist $a,b\in\mathbb{R}$ such that $G(x)=F(ax+b)$. $a$ is called the \emph{scale parameter}, and $b$ the \emph{location parameter} or \emph{centering parameter}.  Let's write $F\stackrel{t}{=}G$ to denote that $F$ and $G$ are of the same type.

\textbf{Remarks}.
\begin{itemize}
\item Necessarily $a&gt;0$, for otherwise at least one of $G(-\infty)=0$ or $G(\infty)=1$ would be violated.
\item If $G(x)=F(x+b)$, then the graph of $G$ is \emph{shifted} to the right from the graph of $F$ by $b$ units, if $b&gt;0$ and to the left if $b&lt;0$.
\item If $G(x)=F(ax)$, then the graph of $G$ is \emph{stretched} from the graph of $F$ by $a$ units if $a&gt;1$, and \emph{compressed} if $a&lt;1$.
\item If $X$ and $Y$ are random variables whose distribution functions are of the same type, say, $F$ and $G$ respectively, and related by $G(x)=F(ax+b)$, then $X$ and $aY+b$ are identically distributed, since $$P(X\le z)=F(z)=G(\frac{z-b}{a})=P(Y \le \frac{z-b}{a})=P(aY+b \le z).$$  When $X$ and $aY+b$ are identically distributed, we write $X \stackrel{t}{=} Y$.
\item Again, suppose $X$ and $Y$ correspond to $F$ and $G$, two distribution functions of the same type related by $G(x)=F(ax+b)$.  Then it is easy to see that $E[X]&lt;\infty$ iff $E[Y]&lt;\infty$.  In fact, if the expectation exists for one, then $E[X]=aE[Y]+b$.  Furthermore, $Var[X]$ is finite iff $Var[Y]$ is.  And in this case, $Var[X]=a^2Var[Y]$.  In general, convergence of moments is a ``typical'' property.
\item We can partition the set of distribution functions into disjoint subsets of functions belonging to the same types, since the binary relation $\stackrel{t}{=}$ is an equivalence relation.
\item By the same token, we can classify all real random variables defined on a fixed probability space according to their distribution functions, so that if $X$ and $Y$ are of the same type $\tau$ iff their corresponding distribution functions $F$ and $G$ are of type $\tau$.
\item Given an equivalence class of distribution functions belonging to a certain type $\tau$, such that a random variable $Y$ of type $\tau$ exists with finite expectation and variance, then there is one distribution function $F$ of type $\tau$ corresponding to a random variable $X$ such that $E[X]=0$ and $Var[X]=1$.  $F$ is called the \emph{standard distribution function} for type $\tau$.  For example, the standard (cumulative) normal distribution is the standard distribution function for the type consisting of all normal distribution functions.
\item Within each type $\tau$, we can further classify the distribution functions: if $G(x)=F(x+b)$, then we say that $G$ and $F$ belong to the same \emph{location family} under $\tau$; and if $G(x)=F(ax)$, then we say that $G$ and $F$ belong to the same \emph{scale family} (under $\tau$).
\end{itemize}</content>
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