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<record version="7" id="8592">
 <title>Riemann curvature tensor</title>
 <name>RiemannCurvatureTensor</name>
 <created>2006-11-28 13:10:15</created>
 <modified>2007-01-29 21:57:55</modified>
 <type>Definition</type>
<parent id="2880">connection</parent>
 <creator id="12619" name="juanman"/>
 <author id="13753" name="Mathprof"/>
 <author id="12619" name="juanman"/>
 <author id="146" name="rmilson"/>
 <classification>
	<category scheme="msc" code="53A55"/>
	<category scheme="msc" code="53B20"/>
 </classification>
 <related>
	<object name="Curvature"/>
	<object name="Connection"/>
	<object name="FormalLogicsAndMetaMathematics"/>
 </related>
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 <content>Let 
$\mathcal{X}$ denote the vector space of smooth vector fields on a
smooth Riemannian manifold $(M,g)$.  Note that $\mathcal{X}$ is actually a
$\mathcal{C}^\infty(M)$ module because we can multiply a vector field
by a function to obtain another vector field.
The \emph{Riemann curvature tensor} is the tri-linear
$\mathcal{C}^\infty$ mapping  
$$R:{\mathcal{X}}\times{\mathcal{X}}\times{\mathcal{X}}\to{\mathcal{X}},$$ 
which is defined by
$$R(X,Y)Z=\nabla_X\nabla_YZ-\nabla_Y\nabla_XZ-\nabla_{[X,Y]}Z$$
where $X,Y,Z\in\mathcal{X}$ are vector fields,  where $\nabla$ is
the Levi-Civita connection attached to the metric tensor $g$, and
where the square brackets denote the Lie bracket of two vector fields.
The tri-linearity means that for every smooth $f\colon M\to\mathbb{R}$
we have
$$fR(X,Y)Z=R(fX,Y)Z=R(X,fY)Z=R(X,Y)fZ.$$

In components this tensor is classically denoted by a set of
four-indexed components ${R^i}_{jkl}$. This means that given a
basis of linearly independent vector fields $X_i$ we have
$$R(X_j,X_k)X_l=\sum_s {R^s}_{jkl}X_s.$$

In a two dimensional manifold it is known that the Gaussian curvature
it is given by
$$K_g=\frac{R_{1212}}{g_{11}g_{22}-{g_{12}}^2}$$</content>
</record>
