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 <title>a closed subset of a complete metric space is complete</title>
 <name>AClosedSubsetOfACompleteMetricSpaceIsComplete</name>
 <created>2006-12-31 10:04:49</created>
 <modified>2006-12-31 10:04:49</modified>
 <type>Result</type>
<parent id="603">complete</parent>
 <creator id="15714" name="ehremo"/>
 <author id="15714" name="ehremo"/>
 <classification>
	<category scheme="msc" code="54E50"/>
 </classification>
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 <content>Let $X$ be a complete metric space, and let $Y \subseteq X$ be a closed subset of $X$. Then $Y$ is complete.

{\bf Proof}

Let $\{ y_n \} \subseteq Y$ be a Cauchy sequence in $Y$. Then by the completeness of $X$, $y_n \rightarrow x$ for some $x \in X$. Then every neighborhood of $x$ contains points in $Y$, so $x \in \overline Y = Y$.</content>
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