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<record version="1" id="8758">
 <title>proof that a finite abelian group has element with $\lvert g\rvert=\exp(G)$</title>
 <name>ProofThatAFiniteAbelianGroupHasElementWithLvertGrvertexpG</name>
 <created>2007-01-14 14:27:50</created>
 <modified>2007-01-14 14:27:50</modified>
 <type>Proof</type>
<parent id="4087">exponent</parent>
 <selfproof>0</selfproof>
 <creator id="10146" name="rm50"/>
 <author id="10146" name="rm50"/>
 <classification>
	<category scheme="msc" code="20A99"/>
 </classification>
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 <content>\begin{thm} If $G$ is a finite abelian group, then $G$ has an element of order $\exp(G)$.
\end{thm}
\textbf{Proof. } Write $\exp(G)=\prod p_i^{k_i}$. Since $\exp(G)$ is the least common multiple of the orders of each group element, it follows that for each $i$, there is an element whose order is a multiple of $p_i^{k_i}$, say $\lvert c_i\rvert=a_i p_i^{k_i}$. Let $d_i=c_i^{a_i}$. Then $\lvert d_i\rvert=p_i^{k_i}$. The $d_i$ thus have pairwise relatively prime orders, and thus
\[\left\lvert\prod d_i\right\rvert=\prod\left\lvert d_i\right\rvert=\exp(G)\]
so that $\prod d_i$ is the desired element.
</content>
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