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<record version="4" id="8921">
 <title>continuous geometry</title>
 <name>ContinuousGeometry</name>
 <created>2007-02-17 02:00:23</created>
 <modified>2008-08-20 20:46:18</modified>
 <type>Definition</type>
 <creator id="3771" name="CWoo"/>
 <author id="3771" name="CWoo"/>
 <classification>
	<category scheme="msc" code="06C20"/>
 </classification>
 <defines>
	<concept>irreducible continuous geometry</concept>
 </defines>
 <synonyms>
	<synonym concept="continuous geometry" alias="von Neumann lattice"/>
 </synonyms>
 <related>
	<object name="LatticeOfProjections"/>
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 <content>Let $V$ be a finite dimensional vector space (over some field) with dimension $n$.  Let $PG(V)$ be its lattice of subspaces, also known as the projective geometry of $V$.  It is well-known that we can associate each element $a\in PG(V)$ a unique integer $\dim(a)$, namely, the dimension of the $a$ as a subspace of $V$.  $\dim$ can be seen as a function from $PG(V)$ to $\mathbb{Z}$.  One property of $\dim$ is that for every $i$ between $0$ and $n$, there is an $a\in PG(V)$ such that $\dim(a)=i$.  If we normalize $\dim$ by dividing its values by $n$, then we get a function $d: PG(V)\to [0,1]$.  As $n$ (the dimension of $V$) increases, the range of $d$ begins to ``fill up'' $[0,1]$.  Of course, we know this is impossible as long as $V$ is finite dimensional.

\underline{Question:} is there a ``geometry'' on which a ``dimension function'' is defined so that it is onto the closed unit interval $[0,1]$?

The answer is yes, and the geometry is the so-called ``continuous geometry''.  However, like projective geometries, it is really just a lattice (with some special conditions).  A continuous geometry $L$ is a generalization of a projective geometry so that a ``continuous'' dimension function $d$ can be defined on $L$ such that for every real number $r\in [0,1]$ there is an $a\in L$ such that $d(a)=r$.  Furthermore, $d$ takes infinite independent joins to infinite sums: $$d(\bigvee_{i=1}^{\infty} a_i)=\sum_{i=1}^{\infty} d(a_i)\mbox{ whenever }a_{j+1}\wedge (\bigvee_{i=1}^{j} a_i)=0\mbox{ for }j\ge 1.$$

\textbf{Definition}.  A \emph{continuous geometry} is a lattice $L$ that is complemented, modular, meet continuous, and join continuous.

From a continuous geometry $L$, it can be shown that the \PMlinkname{perspective}{ComplementedLattice} relation $\thicksim$ on elements of $L$ is a transitive relation (Von Neumann).  Since $\thicksim$ is also reflexive and symmetric, it is an equivalence relation.  In a projective geometry, perspective elements are exactly subspaces having the same dimension.  From this equivalence relation, one can proceed to define a ``dimension'' function from $L$ into $[0,1]$.

Continuous geometry was introduced by Von Neumann in the 1930's when he was working on the theory of operator algebras in Hilbert spaces.  Write $PG(n-1)$ the projective geometry of dimension $n-1$ over $D$ (lattice of left (right) subspaces of left (right) $n$-dimensional vector space over $D$).  Von Neumann found that $PG(n-1)$ can be embedded into $PG(2n-1)$ in such a way that not only the lattice operations are preserved, but the values of the ``normalized dimension function'' $d$ described above are also preserved.  In other words, if $\phi:PG(n-1)\to PG(2n-1)$ is the embedding, and $d_{n}$ is the dimension function on $PG(n-1)$ and $d_{2n}$ is the dimension function on $PG(2n-1)$, then  $d_{n}(a)=d_{2n}(\phi(a))$.  As a result, we get a chain of embeddings $$PG(1)\hookrightarrow PG(3)\hookrightarrow  \cdots \hookrightarrow  PG(2^n-1) \hookrightarrow  \cdots.$$
Taking the union of these lattices, we get a lattice $PG(\infty)$, which is complemented and modular, which has a ``normalized dimension function'' $d$ into $[0,1]$ whose values take the form $p/2^m$ ($p,m$ positive integers).  This $d$ is also a valuation on $PG(\infty)$, turning it into a metric lattice, which in turn can be completed to a lattice $CG(D)$.  This $CG(D)$ is the first example of a continuous geometry having a ``continuous'' dimension function.


\textbf{Remarks}.
\begin{itemize}
\item Any continuous geometry is a complete lattice and a topological lattice if order convergence is used to define a topology on it.
\item An \emph{irreducible continuous geometry} is a continuous geometry whose center is trivial (consisting of just $0$ and $1$).  It turns out that an irreducible continuous geometry is just $CG(D)$ for some division ring $D$. 
\item (Kaplansky) Any orthocomplemented complete modular lattice is a continuous geometry.
\end{itemize}

\begin{thebibliography}{8}
\bibitem{jvn} J. von Neumann, {\em Continuous Geometry}, Princeton, (1960).
\bibitem{gb} G. Birkhoff {\em Lattice Theory}, 3rd Edition, AMS Volume XXV, (1967).
\bibitem{gg} G. Gr\"{a}tzer, {\em General Lattice Theory}, 2nd Edition, Birkh\"{a}user (1998).
\end{thebibliography}</content>
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