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<record version="3" id="9207">
 <title>tight</title>
 <name>Tight</name>
 <created>2007-04-17 16:24:38</created>
 <modified>2007-04-17 20:40:44</modified>
 <type>Definition</type>
<parent id="450">upper bound</parent>
 <creator id="409" name="mps"/>
 <author id="409" name="mps"/>
 <classification>
	<category scheme="msc" code="05D99"/>
 </classification>
 <defines>
	<concept>slack</concept>
 </defines>
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 <content>A bound is \emph{tight} if it can be realized.  A bound that is not
tight is sometimes said to be \emph{slack}.

For example, let $\mathcal{S}$ be the collection of all finite subsets
of $\mathbb{R}^2$ in general position.  Define a function
$g\colon\mathbb{N}\to\mathbb{N}$ as follows.  First, let the weight of
an element $S$ of $\mathcal{S}$ be the size of its largest convex subset,
that is, 
\[
w(S) = \max \{ |T| \colon T\subset S\text{\ and $T$ is convex} \}.
\]
The function $g$ is defined by
\[
g(n) = \min \{ |S| \colon w(S) \ge n\},
\]
that is, $g(n)$ is the smallest number such that any collection of
$g(n)$ points in general position contains a convex $n$-gon.  (By the
\PMlinkname{Erd\H{o}s-Szekeres theorem}{HappyEndingProblem}, $g(n)$ is 
always finite, so $g$ is a well-defined function.)  The bounds for $g$ 
due to Erd\H{o}s and Szekeres are
\[
2^{n-2} + 1\le g(n) \le \binom{2n-4}{n-2} + 1.
\]
The lower bound is tight because for each $n$, there is a set of
$2^{n-2}$ points in general position which contains no convex $n$-gon.
On the other hand, the upper bound is believed to be slack.  In fact, 
according to the Erd\H{o}s-Szekeres conjecture, the formula for $g(n)$ 
is exactly the lower bound: $g(n) = 2^{n-2} + 1$.

\PMlinkescapeword{bound}
\PMlinkescapeword{bounds}
\PMlinkescapeword{size}
\PMlinkescapeword{weight}</content>
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