<?xml version="1.0" encoding="UTF-8"?>

<record version="5" id="9400">
 <title>biangle</title>
 <name>Biangle</name>
 <created>2007-05-19 12:45:09</created>
 <modified>2007-10-27 04:49:56</modified>
 <type>Definition</type>
 <creator id="1863" name="Wkbj79"/>
 <author id="1863" name="Wkbj79"/>
 <classification>
	<category scheme="msc" code="51-00"/>
	<category scheme="msc" code="51M10"/>
 </classification>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}

\usepackage{psfrag}
\usepackage{graphicx}
\usepackage{amsthm}
\usepackage{xypic}
</preamble>
 <content>In spherical geometry, it is possible to form a polygon with only two sides.  Thus, we have the following definition:

A \emph{biangle} is a two-sided polygon that is strictly contained in one hemisphere of the sphere that is serving as the model for spherical geometry.

Given a biangle, its vertices must be antipodal points, and its two angles must be congruent.  Therefore, every biangle is equiangular.  Since each side of a biangle is half of a great circle, every biangle is equilateral.  Hence, every biangle is regular.

Let $\theta$ be the radian \PMlinkname{measure}{AngleMeasure} of each angle of a biangle.  Then the biangle \PMlinkname{covers}{Cover} $\displaystyle \frac{\theta}{2\pi}$ of the sphere.  Since the area of the sphere is $4\pi$, the area of the biangle is $2\theta$.  Note that this equals the angle sum of the biangle.</content>
</record>
