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<record version="6" id="9833">
 <title>table of probabilities of standard normal distribution</title>
 <name>TableOfProbabilitiesOfStandardNormalDistribution</name>
 <created>2007-08-06 00:10:28</created>
 <modified>2007-12-18 11:14:18</modified>
 <type>Definition</type>
<parent id="527">normal random variable</parent>
 <creator id="3771" name="CWoo"/>
 <author id="3771" name="CWoo"/>
 <author id="2872" name="pahio"/>
 <classification>
	<category scheme="msc" code="60E05"/>
	<category scheme="msc" code="62E15"/>
	<category scheme="msc" code="62Q05"/>
 </classification>
 <related>
	<object name="AreaUnderGaussianCurve"/>
 </related>
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 <content>Below is a table of the values of the area (probabilities) $\Phi(z)$ under the standard normal distribution function $N(1,0)=\operatorname{exp}(-x^2/2)$ given by
$$\Phi(z) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^z N(1,0) \, dx\,,$$
evaluated from $-\infty$ to various $z$-scores.  The values are rounded to the nearest ten thousandths.

\footnotesize{
\begin{tabular}{|c||r|r|r|r|r|r|r|r|r|r|}
\hline z-score &amp;\textbf{\red0.00} &amp;\red0.01 &amp;\red0.02 &amp;\textbf{\red0.03} &amp;\red0.04 &amp;\red0.05 &amp;\textbf{\red0.06} &amp;\red0.07 &amp;\red0.08 &amp;\textbf{\red0.09} \\
\hline \hline 0.0 &amp;\textbf{0.5000} &amp;0.5040 &amp;0.5080 &amp;\textbf{0.5120} &amp;0.5160 &amp;0.5199 &amp;\textbf{0.5239} &amp;0.5279 &amp;0.5319 &amp;\textbf{0.5359} \\
\hline 0.1 &amp;\textbf{0.5398} &amp;0.5438 &amp;0.5478 &amp;\textbf{0.5517} &amp;0.5557 &amp;0.5596 &amp;\textbf{0.5636} &amp;0.5675 &amp;0.5714 &amp;\textbf{0.5753} \\
\hline \blue0.2 &amp;\textbf{\blue0.5793} &amp;\blue0.5832 &amp;\blue0.5871 &amp;\textbf{\blue0.5910} &amp;\blue0.5948 &amp;\blue0.5987 &amp;\textbf{\blue0.6026} &amp;\blue0.6064 &amp;\blue0.6103 &amp;\textbf{\blue0.6141} \\
\hline 0.3 &amp;\textbf{0.6179} &amp;0.6217 &amp;0.6255 &amp;\textbf{0.6293} &amp;0.6331 &amp;0.6368 &amp;\textbf{0.6406} &amp;0.6443 &amp;0.6480 &amp;\textbf{0.6517} \\
\hline 0.4 &amp;\textbf{0.6554} &amp;0.6591 &amp;0.6628 &amp;\textbf{0.6664} &amp;0.6700 &amp;0.6736 &amp;\textbf{0.6772} &amp;0.6808 &amp;0.6844 &amp;\textbf{0.6879} \\
\hline \blue0.5 &amp;\textbf{\blue0.6915} &amp;\blue0.6950 &amp;\blue0.6985 &amp;\textbf{\blue0.7019} &amp;\blue0.7054 &amp;\blue0.7088 &amp;\textbf{\blue0.7123} &amp;\blue0.7157 &amp;\blue0.7190 &amp;\textbf{\blue0.7224} \\
\hline 0.6 &amp;\textbf{0.7257} &amp;0.7291 &amp;0.7324 &amp;\textbf{0.7357} &amp;0.7389 &amp;0.7422 &amp;\textbf{0.7454} &amp;0.7486 &amp;0.7517 &amp;\textbf{0.7549} \\
\hline 0.7 &amp;\textbf{0.7580} &amp;0.7611 &amp;0.7642 &amp;\textbf{0.7673} &amp;0.7704 &amp;0.7734 &amp;\textbf{0.7764} &amp;0.7794 &amp;0.7823 &amp;\textbf{0.7852} \\
\hline \blue0.8 &amp;\textbf{\blue0.7881} &amp;\blue0.7910 &amp;\blue0.7939 &amp;\textbf{\blue0.7967} &amp;\blue0.7995 &amp;\blue0.8023 &amp;\textbf{\blue0.8051} &amp;\blue0.8078 &amp;\blue0.8106 &amp;\textbf{\blue0.8133} \\
\hline 0.9 &amp;\textbf{0.8159} &amp;0.8186 &amp;0.8212 &amp;\textbf{0.8238} &amp;0.8264 &amp;0.8289 &amp;\textbf{0.8315} &amp;0.8340 &amp;0.8365 &amp;\textbf{0.8389} \\
\hline 1.0 &amp;\textbf{0.8413} &amp;0.8438 &amp;0.8461 &amp;\textbf{0.8485} &amp;0.8508 &amp;0.8531 &amp;\textbf{0.8554} &amp;0.8577 &amp;0.8599 &amp;\textbf{0.8621} \\
\hline \blue1.1 &amp;\textbf{\blue0.8643} &amp;\blue0.8665 &amp;\blue0.8686 &amp;\textbf{\blue0.8708} &amp;\blue0.8729 &amp;\blue0.8749 &amp;\textbf{\blue0.8770} &amp;\blue0.8790 &amp;\blue0.8810 &amp;\textbf{\blue0.8830} \\
\hline 1.2 &amp;\textbf{0.8849} &amp;0.8869 &amp;0.8888 &amp;\textbf{0.8907} &amp;0.8925 &amp;0.8944 &amp;\textbf{0.8962} &amp;0.8980 &amp;0.8997 &amp;\textbf{0.9015} \\
\hline 1.3 &amp;\textbf{0.9032} &amp;0.9049 &amp;0.9066 &amp;\textbf{0.9082} &amp;0.9099 &amp;0.9115 &amp;\textbf{0.9131} &amp;0.9147 &amp;0.9162 &amp;\textbf{0.9177} \\
\hline \blue1.4 &amp;\textbf{\blue0.9192} &amp;\blue0.9207 &amp;\blue0.9222 &amp;\textbf{\blue0.9236} &amp;\blue0.9251 &amp;\blue0.9265 &amp;\textbf{\blue0.9279} &amp;\blue0.9292 &amp;\blue0.9306 &amp;\textbf{\blue0.9319} \\
\hline 1.5 &amp;\textbf{0.9332} &amp;0.9345 &amp;0.9357 &amp;\textbf{0.9370} &amp;0.9382 &amp;0.9394 &amp;\textbf{0.9406} &amp;0.9418 &amp;0.9429 &amp;\textbf{0.9441} \\
\hline 1.6 &amp;\textbf{0.9452} &amp;0.9463 &amp;0.9474 &amp;\textbf{0.9484} &amp;0.9495 &amp;0.9505 &amp;\textbf{0.9515} &amp;0.9525 &amp;0.9535 &amp;\textbf{0.9545} \\
\hline \blue1.7 &amp;\textbf{\blue0.9554} &amp;\blue0.9564 &amp;\blue0.9573 &amp;\textbf{\blue0.9582} &amp;\blue0.9591 &amp;\blue0.9599 &amp;\textbf{\blue0.9608} &amp;\blue0.9616 &amp;\blue0.9625 &amp;\textbf{\blue0.9633} \\
\hline 1.8 &amp;\textbf{0.9641} &amp;0.9649 &amp;0.9656 &amp;\textbf{0.9664} &amp;0.9671 &amp;0.9678 &amp;\textbf{0.9686} &amp;0.9693 &amp;0.9699 &amp;\textbf{0.9706} \\
\hline 1.9 &amp;\textbf{0.9713} &amp;0.9719 &amp;0.9726 &amp;\textbf{0.9732} &amp;0.9738 &amp;0.9744 &amp;\textbf{0.9750} &amp;0.9756 &amp;0.9761 &amp;\textbf{0.9767} \\
\hline \blue2.0 &amp;\textbf{\blue0.9772} &amp;\blue0.9778 &amp;\blue0.9783 &amp;\textbf{\blue0.9788} &amp;\blue0.9793 &amp;\blue0.9798 &amp;\textbf{\blue0.9803} &amp;\blue0.9808 &amp;\blue0.9812 &amp;\textbf{\blue0.9817} \\
\hline 2.1 &amp;\textbf{0.9821} &amp;0.9826 &amp;0.9830 &amp;\textbf{0.9834} &amp;0.9838 &amp;0.9842 &amp;\textbf{0.9846} &amp;0.9850 &amp;0.9854 &amp;\textbf{0.9857} \\
\hline 2.2 &amp;\textbf{0.9861} &amp;0.9864 &amp;0.9868 &amp;\textbf{0.9871} &amp;0.9875 &amp;0.9878 &amp;\textbf{0.9881} &amp;0.9884 &amp;0.9887 &amp;\textbf{0.9890} \\
\hline \blue2.3 &amp;\textbf{\blue0.9893} &amp;\blue0.9896 &amp;\blue0.9898 &amp;\textbf{\blue0.9901} &amp;\blue0.9904 &amp;\blue0.9906 &amp;\textbf{\blue0.9909} &amp;\blue0.9911 &amp;\blue0.9913 &amp;\textbf{\blue0.9916} \\
\hline 2.4 &amp;\textbf{0.9918} &amp;0.9920 &amp;0.9922 &amp;\textbf{0.9925} &amp;0.9927 &amp;0.9929 &amp;\textbf{0.9931} &amp;0.9932 &amp;0.9934 &amp;\textbf{0.9936} \\
\hline 2.5 &amp;\textbf{0.9938} &amp;0.9940 &amp;0.9941 &amp;\textbf{0.9943} &amp;0.9945 &amp;0.9946 &amp;\textbf{0.9948} &amp;0.9949 &amp;0.9951 &amp;\textbf{0.9952} \\
\hline \blue2.6 &amp;\textbf{\blue0.9953} &amp;\blue0.9955 &amp;\blue0.9956 &amp;\textbf{\blue0.9957} &amp;\blue0.9959 &amp;\blue0.9960 &amp;\textbf{\blue0.9961} &amp;\blue0.9962 &amp;\blue0.9963 &amp;\textbf{\blue0.9964} \\
\hline 2.7 &amp;\textbf{0.9965} &amp;0.9966 &amp;0.9967 &amp;\textbf{0.9968} &amp;0.9969 &amp;0.9970 &amp;\textbf{0.9971} &amp;0.9972 &amp;0.9973 &amp;\textbf{0.9974} \\
\hline 2.8 &amp;\textbf{0.9974} &amp;0.9975 &amp;0.9976 &amp;\textbf{0.9977} &amp;0.9977 &amp;0.9978 &amp;\textbf{0.9979} &amp;0.9979 &amp;0.9980 &amp;\textbf{0.9981} \\
\hline \blue2.9 &amp;\textbf{\blue0.9981} &amp;\blue0.9982 &amp;\blue0.9982 &amp;\textbf{\blue0.9983} &amp;\blue0.9984 &amp;\blue0.9984 &amp;\textbf{\blue0.9985} &amp;\blue0.9985 &amp;\blue0.9986 &amp;\textbf{\blue0.9986} \\
\hline 3.0 &amp;\textbf{0.9987} &amp;0.9987 &amp;0.9987 &amp;\textbf{0.9988} &amp;0.9988 &amp;0.9989 &amp;\textbf{0.9989} &amp;0.9989 &amp;0.9990 &amp;\textbf{0.9990} \\
\hline 3.1 &amp;\textbf{0.9990} &amp;0.9991 &amp;0.9991 &amp;\textbf{0.9991} &amp;0.9992 &amp;0.9992 &amp;\textbf{0.9992} &amp;0.9992 &amp;0.9993 &amp;\textbf{0.9993} \\
\hline \blue3.2 &amp;\textbf{\blue0.9993} &amp;\blue0.9993 &amp;\blue0.9994 &amp;\textbf{\blue0.9994} &amp;\blue0.9994 &amp;\blue0.9994 &amp;\textbf{\blue0.9994} &amp;\blue0.9995 &amp;\blue0.9995 &amp;\textbf{\blue0.9995} \\
\hline 3.3 &amp;\textbf{0.9995} &amp;0.9995 &amp;0.9995 &amp;\textbf{0.9996} &amp;0.9996 &amp;0.9996 &amp;\textbf{0.9996} &amp;0.9996 &amp;0.9996 &amp;\textbf{0.9997} \\
\hline 3.3 &amp;\textbf{0.9995} &amp;0.9995 &amp;0.9995 &amp;\textbf{0.9996} &amp;0.9996 &amp;0.9996 &amp;\textbf{0.9996} &amp;0.9996 &amp;0.9996 &amp;\textbf{0.9997} \\
\hline \blue3.4 &amp;\textbf{\blue0.9997} &amp;\blue0.9997 &amp;\blue0.9997 &amp;\textbf{\blue0.9997} &amp;\blue0.9997 &amp;\blue0.9997 &amp;\textbf{\blue0.9997} &amp;\blue0.9997 &amp;\blue0.9997 &amp;\textbf{\blue0.9998} \\
\hline 3.5 &amp;\textbf{0.9998} &amp;0.9998 &amp;0.9998 &amp;\textbf{0.9998} &amp;0.9998 &amp;0.9998 &amp;\textbf{0.9998} &amp;0.9998 &amp;0.9998 &amp;\textbf{0.9998} \\
\hline 3.6 &amp;\textbf{0.9998} &amp;0.9998 &amp;0.9999 &amp;\textbf{0.9999} &amp;0.9999 &amp;0.9999 &amp;\textbf{0.9999} &amp;0.9999 &amp;0.9999 &amp;\textbf{0.9999} \\
\hline \blue3.7 &amp;\textbf{\blue0.9999} &amp;\blue0.9999 &amp;\blue0.9999 &amp;\textbf{\blue0.9999} &amp;\blue0.9999 &amp;\blue0.9999 &amp;\textbf{\blue0.9999} &amp;\blue0.9999 &amp;\blue0.9999 &amp;\textbf{\blue0.9999} \\
\hline 3.8 &amp;\textbf{0.9999} &amp;0.9999 &amp;0.9999 &amp;\textbf{0.9999} &amp;0.9999 &amp;0.9999 &amp;\textbf{0.9999} &amp;0.9999 &amp;0.9999 &amp;\textbf{0.9999} \\
\hline 3.9 &amp;\textbf{1.0000} &amp;1.0000 &amp;1.0000 &amp;\textbf{1.0000} &amp;1.0000 &amp;1.0000 &amp;\textbf{1.0000} &amp;1.0000 &amp;1.0000 &amp;\textbf{1.0000} \\
\hline \blue4.0 &amp;\textbf{\blue1.0000} &amp;\blue1.0000 &amp;\blue1.0000 &amp;\textbf{\blue1.0000} &amp;\blue1.0000 &amp;\blue1.0000 &amp;\textbf{\blue1.0000} &amp;\blue1.0000 &amp;\blue1.0000 &amp;\textbf{\blue1.0000} \\
\hline
\end{tabular}}

\normalsize
Graphically, this looks like

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\psset{yunit=4cm,xunit=4}
\begin{pspicture}(-2,-0.2)(2,1)
\psaxes{-&gt;}(0,0)(-2,0)(2,1)
  \uput[-90](2,0){x}\uput[0](0,0.9){y}
  \psplot{-1.8}{1.8}{2.718282 x 2 mul 2 exp neg 2 div exp 0.75 mul }
     \psclip{
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 \endpsclip
\rput[t](0.4,-0.05){$z$} 
\rput[t](-0.1,0.4){$\Phi(z)$}
\end{pspicture}

where the curve is the probability density function $N(0,1)$ of the standard normal distribution (with mean $0$ and standard deviation $1$), $z$ on the $x$-axis is the $z$-score, and $\Phi(z)$ (represented by the light gray region) is the area bounded by $N(0,1)$, the $x$-axis, and $x\le z$.

\subsubsection*{Finding $\Phi(z)$ from $z$}  

Given a $z$-score, one can easily find $\Phi(z)$ as follows: 
\begin{enumerate}
\item round the $z$-score $z$ to the nearest hundredths decimal place; for example, if $z=1.2345$, then rounding it to the hundredths gives you $1.23$.
\item
if $0\le z\le 4$, write $z=a+b$, where $a$ is the truncation of $r$ at the tenths place, and $b=r-a$; for example, if $z=1.23$, then $a=1.2$ and $b=0.03$.
\item
locate $a$ in the first column of the table, and then locate $b$ in the first row of the table
\item 
find the value in the cell corresponding to row $a$ and column $b$; this value is $\Phi(z)$; for example, if $a=1.2$ and $b=0.03$, then the corresponding value is $0.8907$.
\end{enumerate}

If $z&gt;4$, then $\Phi(z)=1$ when rounded to the nearest ten thousandths.  If $z&lt;0$, then we will not be able to use the table above.  However, since $N(0,1)$ is an even function, $\Phi(z)$, the area bounded by $N(0,1)$, the $x$-axis, and $x\le z$ is the same as the area bounded by $N(0,1)$, the $x$-axis, and $x\ge -z$, which is equal to $1-\Phi(-z)$.  These two facts can be summarized:
\begin{enumerate}
\item If $z&gt;4$, then $\Phi(z)=1$ when rounded to the nearest ten thousandths to the right of the decimal point.
\item If $z&lt;0$, then use the formula $\Phi(z)=1-\Phi(-z)$ before applying the table.  For example, $\Phi(-1.23)=1-\Phi(1.23)=1-0.8907=0.1093$.
\end{enumerate}

Also, we may use linear interpolation to find (approximate) $\Phi(z)$ for any arbitrary $z$-score.  For example, if we want to compute $\Phi(1.234)$, then we first find $\Phi(1.23)$ and $\Phi(1.24)$.  Then $$\Phi(1.234)\approx 0.6\cdot \Phi(1.23)+ 0.4\cdot \Phi(1.24)=0.6\cdot 0.8907+0.4\cdot 0.8925 \approx 0.8914.$$

\subsubsection*{Finding $z$ from $\Phi(z)$}  

Given $\Phi(z)$, we may use the table to find $z$.  The process works in reverse of the process presented in the previous section:
\begin{enumerate}
\item round $r=\Phi(z)$ to the nearest ten thousandths; for example if $\Phi(z)=0.91236$, then $r=0.9124$ after rounding
\item if $0.5\le r\le 1$, then find the cell in the table with value as close to $r$ as possible; for example, for $r=0.9124$, the closest value that can be found in the table is $0.9131$
\item if this cell is found, then find the corresponding value $a$ in the first column and $b$ in the first row, and $z^*=a+b$ is the approximate $z$-score that we are looking for; for example, $0.9131$ corresponds to $a=1.3$ and $b=0.06$ so that $z^*=1.36$.
\item if $\Phi(z)&lt;0.5$, then use $r=1-\Phi(z)$ to find $z^*$ using the first three steps above.  Then $z=-z^*$ is the $z$-score that we are looking for.
\end{enumerate}

Note that if $\Phi(z)=1$, then any $z\ge 3.9$ will work.  Also, linear interpolation can again be applied to get better approximations of the $z$-scores given $\Phi(z)$.  For example, $\Phi(z)=0.91236$ is between $0.9115$ and $0.9131$, two consecutive values found in the table, and can be written 
$$0.91236 \approx 0.4625 \cdot 0.9115 + 0.5375 \cdot 0.9131.$$
So, the $z$-score corresponding to $0.91236$ can be obtained similarly
$$0.4625 \cdot 1.35 + 0.5375 \cdot 1.36 \approx 1.3554 \approx z,$$
where $1.35$ is the $z$-score for $0.9115$ and $1.36$ is the $z$-score for $0.9131$.</content>
</record>
