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![[parent]](http://images.planetmath.org:8080/images/uparrow.png) Viewing Message
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| ``Re: related problem''
by pahio on 2006-08-26 15:56:12 |
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| If r is distinct from zero, you can divide the inequality by |r|, getting
|A-b/r| <= c/|r|.
Thus A may be any integer between b/r-c/|r| and b/r+c/|r|.
Regards,
Jussi |
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