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| ``Re: a note about 11| { }''
by perucho on 2006-09-13 21:38:25 |
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| Thanks to you! It was your idea! No problem; I already gave you full access to the entry and you can make the changes that you consider convenient. Also, I have checked $(ELPN)_n$ (Eq.(6)) for a binary base and 6-length. So, $b=2$, $n=3$. I took: $b_0=b_1=1$,$b_2=0$. By using $3=1.2^0+1.2^1=11$, I did the multiplication $10001x11$ and I got the Even Length Palindromic Number=$(ELPN)_3= 110011$. If you like you may add this example. perucho |
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