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![[parent]](http://images.planetmath.org:8080/images/uparrow.png) Viewing Message
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| ``Re: Half of Bhaskara's proof''
by rspuzio on 2007-05-26 12:17:41 |
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| The diagram Bhaskara used was a square of length a+b which was
cut into four right traiangles of sides a,b,c and a square of
length c.
By the way, there is also a purely geometric way of presenting
Bhaskara's proof. Namely, one considers two differrent ways of
subdividing the square of length a+b. One is as above. The
other divides it into a square of side a, a square of side b and
four triangles of sides a,b,c. By comparing these subdivisions,
it is obvious that a^2 + b^2 = c^2.
Based on how you did your entry, I will add an account of this proof.
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