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![[parent]](http://images.planetmath.org:8080/images/uparrow.png) Viewing Message
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| ``Re: Proof''
by mathcam on 2007-12-27 11:25:11 |
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| Something's wrong there -- if a polynomial f with real coefficients has all real roots (say a_1,...,a_n) then it's necessarily reducible -- it factors into linear factors as
f(x) = a(x-a_1)(x-a_2)...(x-a_n)
for some constant a.
Ah, after doing some reading -- it appears that the "irreducibilis" in this phrase is not related to the irreducibility of the polynomial. The page casus irreducibilis entry should remove the irreducibility hypothesis.
Cam
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