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![[parent]](http://images.planetmath.org:8080/images/uparrow.png) Viewing Message
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| ``Re: Proof''
by pahio on 2007-12-28 12:17:09 |
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| Dear Cam, your example equation really has three real roots, but they are not rational. And since the trinomial of the left side is in Q[x], it cannot be split in that ring into factors of less degree -- so it is irreducible.
BTW, the roots are the sums of the cube roots of 2+11i and 2-11i multiplied by a third root of unity and its square, resp.
Jussi |
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