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| ``request "integration" 2008-3-5''
by pahio on 2008-03-05 12:17:38 |
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| itsiffi,
For convergence of the integral the coefficient (ia) of y^2 must be negative. It were clearer that instead of "ia" you write e.g. -a.
See the entry
http://planetmath.org/encyclopedia/AreaUnderGaussianCurve.html
Perform the substitution
y = t/\sqrt{a}, dy = dt/\sqrt{a}.
You will easily obtain the result \sqrt{\pi/a}.
Jussi |
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