PlanetMath (more info)
 Math for the people, by the people. Sponsor PlanetMath
Encyclopedia | Requests | Forums | Docs | Wiki | Random | RSS  
Login
create new user
name:
pass:
forget your password?
Main Menu
[parent] Viewing Message
``Re: invariants of the tensor product'' by mcintosh on 2003-10-06 23:02:56
Allright, why not try to make it more illuminating? Those
wedgies are determinants, the trace takes sums, and the final
form looks like a convolution. But I'm suspicious of anything
that starts off with something depending only on A; the
determinant of the tensor product doesn't look like that,
although the trace does. Call those wedgies, which are the
symmatric functions of the roots, sigma-k. Then Sigma-2 (for
the tensor product) would be sigma-2-A + sigma-1-A * sigma-1-B
+ sigma-2-B. Is that correct?

Is it possible to run this in Mathematica(TM) and get a human-
readable result?

[ reply | up | top ]
Interact
reply