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![[parent]](http://images.planetmath.org:8080/images/uparrow.png) Viewing Message
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| ``Re: Solving second order linear ODE''
by perucho on 2009-11-03 11:25:52 |
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| d^2u/dx^2 + P(x)du/dx+Q(x)u=0
Let's find the self-adjoint equation. Let's define
R(x)=e^{\int P(x)dx},
and
S(x)=Q(x)R(x).
So your equation is now
d/dx[R(x)du/dx]+S(x)u=0.
Now it's yours.
peruchin
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