|
|
Viewing Message
|
|
|
| ``Re: Proving the Null(A)=Null(U)''
by cayley on 2009-11-05 18:13:26 |
|
| I assume this is in connection with the factorization A=LU. The standard convention is that L is unit lower triangular and therefore invertible. If L was not invertible the statement wouldn't be true. Here's half the proof. If x is in Nul U then Ux=0. It then follows that LUX=0 and so Ax=0. x is therefore in Nul A. |
| | [ reply | up | top ] |
|
|
|
|
|
|