|
|
Viewing Message
|
|
|
| ``Re: Proof of Chebyshev's inequality by induction''
by vernondalhart on 2004-05-19 08:14:36 |
|
| From a proper axiomatic standpoint, you're certainly correct. But while technically everything in mathematics should be derived from the axioms, this is often not really the case.
Really, I think his point was that if you can show something for an arbitrary integer $n$, then you've shown that it holds true for all $n$. I mean, if it only depends on that one value $n$ and on none of the $m \le n$, then that is basically a proof by induction, just a remarkably simple one. |
| | [ reply | up | top ] |
|
|
|
|
|
|