[p] **Another good book** by akdevaraj Mar 27"Prime obsession " by John Derbyshire - it is on Riemann Hypothesis-
extremely readable.

**pstricks** by Wkbj79 Mar 15>

[p] **Deleting** by akdevaraj Feb 15How do we delete a message; I clicked on edit.then tried to delete
but did not succeed.

[p] **Indirect primality testing** by perucho Feb 15Thanks akdevaraj for clarify what "*" means. k* confused me since here in PM one simply writes f(x+kf(x)). Your example is quite complex, so f(x+kf(x)) is too long. But let's suppose f(x)=x^2, so f(x+kf(x))=f(x+kx^2)=(x+kx^2)^2=k^2x^4+2kx^3+x^2.
Let's prove a couple of examples. If k=0, f(x+0f(x))=0^2x^4+2(0)x^3+x^2=x^2=f(x) as it should be. If k=1, f(x+1f(x))=1^2x^4+2(1)x^3+x^2=x^2+2x^3+x^4=(x+x^2)^2=f(x+x^2), again as it should be. Thus I can't understand what you are trying to do. Greetings.

[p] **Approximate values of real** by RKJCHENNAI Feb 11http://rkmath.yolasite.com/resources/Roots%20sum%20and%20multiplication.pdf

** Finding approximate values of real roots equation. ** by RKJCHENNAI Feb 11>

[p] **search engine** by akdevaraj Feb 4Search engine still not functioning!

[p] **Legendre's symbol** by akdevaraj Jan 29(a/p) is the Legendre symbol for quadratic residues and non-residues.
If (a/p) = -1 it means a is not a quadratic residue of p.
Another way of expressing this: the p (under ref ) is an
impossible prime factor of (x^2 - a ).For further examples of this
concept see A123239, A 072936 and A 119691 on OEIS.

[p] **Book** by akdevaraj Jan 26Currently reading "prime numbers - a computational
perspective" by Richard Crandall and Carl Pomerance.
This is a monumental book on prime numbers, primality
testing and factorisation.

[p] **Book** by akdevaraj Jan 26Currently reading "prime numbers - a computational
perspective" by Richard Crandall and Carl Pomerance.
This is a monumental book on prime numbers, primality
testing and factorisation.

[p] **Book** by akdevaraj Jan 26Currently reading "prime numbers - a computational
perspective" by Richard Crandall and Carl Pomerance.
This is a monumental book on prime numbers, primality
testing and factorisation.

[p] **Indirect primality testing** by akdevaraj Jan 24Dear dh2718, thanks for the compliment.

[p] **Indirect primality testing** by akdevaraj Jan 23Dear Permalink-you are right about bio-age; I am 85.

[p] **Indirect primality testing** by akdevaraj Jan 13Dear Peruchio - f(x+k*f(x)) - star means "multiply". k belongs to Z
Thus in this case since f(x) = x^2+x+1, f(x+k*f(x)) means 1 + 3k.
Trust this is clear.