Substituting $x := \frac{1}{2}$ to the equation (1) yields $$\frac{1}{4} \;=\; \frac{1}{6}-\frac{1}{\pi^2}\sum_{n=1}^\infty\frac{\cos{n\pi}}{n^2} \;=\; \frac{1}{6}+\frac{1}{\pi^2}\sum_{n=1}^\infty\frac{(-1)^{n+1}}{n^2},$$ which we can solve to the form