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[parent] a Lebesgue measurable but non-Borel set (Theorem)

We give an example of a subset of the real numbers which is Lebesgue measurable, but not Borel measurable.

Let $S$ consist of the set of all irrational real numbers with continued fraction of the form \begin{equation*} x=a_0+\sfrac{1}{a_1+\sfrac{1}{a_2+\sfrac{1}{\ddots}}} \end{equation*}such that there exists an infinite sequence $0<i_1<i_2<\cdots$ where each $a_{i_k}$ divides $a_{i_{k+1}}$ . It can be shown that this set is Lebesgue measurable, but not Borel measurable.

In fact, it can be shown that $S$ is an analytic set, meaning that it is the image of a continuous function $f\colon X\rightarrow\mathbb{R}$ for some Polish space $X$ and, consequently, $S$ is a universally measurable set.

This example is due to Lusin (1927).




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Keywords:  Lebesgue measurable, Borel measurable, continued fraction

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Cross-references: universally measurable, Polish space, continuous function, image, sequence, infinite, continued fraction, irrational, Borel measurable, Lebesgue measurable, real numbers, subset
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This is version 3 of a Lebesgue measurable but non-Borel set, born on 2008-12-15, modified 2009-02-01.
Object id is 11351, canonical name is ALebesgueMeasurableButNonBorelSet.
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Classification:
AMS MSC28A05 (Measure and integration :: Classical measure theory :: Classes of sets , measurable sets, Suslin sets, analytic sets)
 28A20 (Measure and integration :: Classical measure theory :: Measurable and nonmeasurable functions, sequences of measurable functions, modes of convergence)

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