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[parent] intercept theorem (Theorem)

Theorem. If two intersecting lines are cut by parallel lines, the line segments cut by the parallel lines from one of the lines are proportional to the corresponding line segments cut by them from the other line.

The theorem may be condensed to the following form:

The intercept theorem has been known by the ancient Babylonians and Egyptians, but the first known proof is found in Euclid's Elements.

Proof. The areas of triangles, which have equal heights, are proportional to the bases of the triangles; if the bases are equal, then also the areas are equal. These facts are used in the chain $$BD:DA \;=\; \Delta BDE : \Delta DAE \;=\; \Delta CED : \Delta EAD \;=\; CE:EA$$ of equalities. Q.E.D.


\begin{pspicture}(-3,-0.5)(3,5.4) \rput(-3,-0.5){.} \rput(3,5.4){.} \pspolygon(-... ...} \rput(2.2,-0.2){$C$} \rput(-1.36,1.5){$D$} \rput(1.9,1.5){$E$} \end{pspicture}




"intercept theorem" is owned by pahio.
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See Also: area of a polygonal region, similar triangles, mid-segment theorem

Keywords:  similar triangles

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$n$-section of line segment with compass and straightedge (Algorithm) by pahio
construction of fourth proportional (Application) by pahio
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Cross-references: equalities, bases, heights, areas, proof, proportion equation, points, sides, intersects, triangle, parallel, line segments, parallel lines, cut, lines, theorem
There are 2 references to this entry.

This is version 5 of intercept theorem, born on 2009-02-16, modified 2009-02-21.
Object id is 11632, canonical name is InterceptTheorem.
Accessed 753 times total.

Classification:
AMS MSC51-01 (Geometry :: Instructional exposition )
 51M04 (Geometry :: Real and complex geometry :: Elementary problems in Euclidean geometries)

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