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proof of principle of transfinite induction
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(Proof)
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To prove the transfinite induction theorem, we note that the class of ordinals is well-ordered by $\in$ . So suppose for some $\Phi$ , there are ordinals $\alpha$ such that $\Phi(\alpha)$ is not true. Suppose further that $\Phi$ satisfies the hypothesis, i.e. $\forall\alpha(\forall\beta<\alpha(\Phi(\beta))\Rightarrow\Phi(\alpha))$ . We will reach a contradiction.
The class $C=\{\alpha:\neg\Phi(\alpha)\}$ is not empty. Note that it may be a proper class, but this is not important. Let $\gamma=\min(C)$ be the $\in$ -minimal element of $C$ . Then by assumption, for every $\lambda<\gamma$ , $\Phi(\lambda)$ is true. Thus, by hypothesis, $\Phi(\gamma)$ is true, contradiction.
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"proof of principle of transfinite induction" is owned by jihemme. [ full author list (2) | owner history (1) ]
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| Keywords: |
well ordered set |
This object's parent.
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Cross-references: proper class, class, contradiction, hypothesis, satisfies, ordinals, well-ordered, class of ordinals, theorem, transfinite induction
This is version 8 of proof of principle of transfinite induction, born on 2002-02-25, modified 2002-06-01.
Object id is 2704, canonical name is ProofOfPrincipleOfTransfiniteInduction.
Accessed 3577 times total.
Classification:
| AMS MSC: | 03B10 (Mathematical logic and foundations :: General logic :: Classical first-order logic) |
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Pending Errata and Addenda
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