|
|
|
|
the ring of integers of a number field is finitely generated over
|
(Theorem)
|
|
Proof. [Proof of the corollary] By the theorem, $\mathcal{O}_K$ is a free abelian group of rank $n$ , and therefore it is finitely generated. Notice that an ideal is an additive subgroup. Finally a subgroup of a finitely generated free abelian group is also finitely generated. 
This is the first step to prove that $\mathcal{O}_K$ is a Dedekind domain. Notice that the field of fractions of $\mathcal{O}_K$ is the field $K$ itself. Therefore, by definition, $\mathcal{O}_K$ is integrally closed in $K$ .
|
"the ring of integers of a number field is finitely generated over " is owned by alozano.
|
|
(view preamble | get metadata)
Cross-references: integrally closed, field, field of fractions, Dedekind domain, subgroup, additive, theorem, finitely generated, ideal, combination, algebraic integers, integral basis, finite, rank, free abelian group, ring, ring of integers, degree, number field
There is 1 reference to this entry.
This is version 4 of the ring of integers of a number field is finitely generated over , born on 2005-03-17, modified 2005-03-17.
Object id is 6883, canonical name is RingOfIntegersOfANumberFieldIsFinitelyGeneratedOverMathbbZ.
Accessed 2039 times total.
Classification:
| AMS MSC: | 13B22 (Commutative rings and algebras :: Ring extensions and related topics :: Integral closure of rings and ideals ; integrally closed rings, related rings ) |
|
|
|
|
|
|
Pending Errata and Addenda
|
|
|
|
|
|
|
|
|
|
|