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About
every algebraically closed field is perfect
(Result)
Proposition
1
Every algebraically closed field is perfect
Proof
. Let
$K$
be an
algebraically closed
field
of
prime
characteristic
$p$
Take
$a\in K$
Then the
polynomial
$X^p-a$
admits a zero in
$K$
It follows that
$a$
admits a
$p$
root
in
$K$
Since
$a$
is arbitrary we have proved that the field
$K$
is
perfect
.
"every algebraically closed field is perfect" is owned by
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Cross-references:
perfect
,
root
,
polynomial
,
characteristic
,
prime
,
field
,
algebraically closed
This is
version 3
of
every algebraically closed field is perfect
, born on 2007-04-01, modified 2007-04-02.
Object id is
9139
, canonical name is
DerivationOfAlgebraicallyClosed
.
Accessed 880 times total.
Classification:
AMS MSC
:
12F05
(Field theory and polynomials :: Field extensions :: Algebraic extensions)
Pending Errata and Addenda
None.
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