|
|
|
|
convex functions lie above their supporting lines
|
(Result)
|
|
|
Let $f:\mathbf{R}\rightarrow \mathbf{R}$ be a convex, twice differentiable function on $[a,b]$ . Then $f(x)$ lies above its supporting lines, i.e. it's greater than any tangent line in $[a,b]$ .
Proof. :
Let $r(x)=f\left( x_{0}\right) +f^{\prime }\left( x_{0}\right) \left( x-x_{0}\right) $ be the tangent of $f(x)$ in $x=x_{0}\in \lbrack a,b].$
By Taylor theorem, with remainder in Lagrange form, one has, for any $x\in \lbrack a,b]$ : $$ f\left( x\right) =f\left( x_{0}\right) +f^{\prime }\left( x_{0}\right) \left( x-x_{0}\right) +\frac{1}{2}f^{^{\prime \prime }}\left( \xi \left( x\right) \right) \left( x-x_{0}\right) ^{2} $$ with $\xi \left( x\right) \in \lbrack a,b]$ . Then $$ f\left( x\right) -r(x)=\frac{1}{2}f^{^{\prime \prime }}\left( \xi \left( x\right) \right) \left( x-x_{0}\right) ^{2}\geq 0 $$ since $f^{^{\prime \prime }}\left( \xi \left( x\right) \right) \geq 0$ by convexity. 
|
"convex functions lie above their supporting lines" is owned by Andrea Ambrosio.
|
|
(view preamble | get metadata)
Cross-references: remainder, Taylor theorem, tangent line, lines, function, twice differentiable, convex
There is 1 reference to this entry.
This is version 2 of convex functions lie above their supporting lines, born on 2007-04-26, modified 2007-05-23.
Object id is 9268, canonical name is ConvexFunctionsLieAboveTheirSupportingLines.
Accessed 1032 times total.
Classification:
| AMS MSC: | 26B25 (Real functions :: Functions of several variables :: Convexity, generalizations) | | | 26A51 (Real functions :: Functions of one variable :: Convexity, generalizations) | | | 52A41 (Convex and discrete geometry :: General convexity :: Convex functions and convex programs) |
|
|
|
|
|
|
Pending Errata and Addenda
|
|
|
|
|
|
|
|
|
|
|