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[parent] quotients of Banach spaces by closed subspaces are Banach spaces under the quotient norm (Theorem)

Theorem - Let $X$ be a Banach space and $M$ a closed subspace. Then $X/M$ with the quotient norm is a Banach space.

Proof : In order to prove that $X/M$ is a Banach space it is enough to prove that every series in $X/M$ that converges absolutely also converges in $X/M$ .

Let $\sum_{n} X_n$ be an absolutely convergent series in $X/M$ , i.e., $\sum_{n} \|X_n\|_{X/M} < \infty$ . By definition of the quotient norm, there exists $x_n \in X_n$ such that

$\displaystyle \Vert x_n \Vert \le \Vert X_n \Vert _{X/M} + 2^{-n} $

It is clear that $\sum_{n} \|x_n\| < \infty$ and so, as $X$ is a Banach space, $\sum_{n} x_n$ is convergent.

Let $x = \sum_{n} x_n$ and $s_k = \sum_{n=1}^k x_n$ . We have that

$\displaystyle x - s_k + M = (x+M) - (s_k +M) = (x+M) - \sum_{n=1}^k (x_n +M) = (x+M) - \sum_{n=1}^k X_n $

Since $\|x-s_k + M \|_{X/M} \leq \|x-s_k\| \longrightarrow 0$ we see that $\sum_n X_n$ converges in $X/M$ to $x+M$ . $\square$




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Cross-references: convergent, clear, absolutely convergent, converges, converges absolutely, series, proof, quotient norm, subspace, closed, Banach space, theorem
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This is version 4 of quotients of Banach spaces by closed subspaces are Banach spaces under the quotient norm, born on 2007-07-07, modified 2007-07-27.
Object id is 9750, canonical name is QuotientsOfBanachSpacesByClosedSubspacesAreBanachSpacesUnderTheQuotientNorm.
Accessed 1093 times total.

Classification:
AMS MSC46B99 (Functional analysis :: Normed linear spaces and Banach spaces; Banach lattices :: Miscellaneous)

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