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area (Definition)

The area of a two-dimensional figure is the amount of space contained within the figure. Area is typically measured in square units; i.e., if the area of a figure is 5 ${in}^2$ , this means that, if five 1 inch by 1 inch squares are cut appropriately, they can be arranged so that they exactly cover the space contained in the figure without any overlapping. In formulas, area is almost always denoted using the letter $A$ .

All examples provided within this entry are in Euclidean geometry.

For certain figures, area is quite commonly found by multiplying the lengths of two line segments which are related to the figure as well as perpendicular to each other. Below are some examples:

  • triangle: $\displaystyle A=\frac{1}{2}bh$ , where $b$ is its base and $h$ is its height

    \begin{pspicture}(-1,-2)(5,4) \psline(0,0)(2,4)(5,0)(0,0) \rput[b](0,0){.} \rput... ...put[r](2,2){$h$} \psline(2,0.3)(2.3,0.3) \psline(2.3,0.3)(2.3,0) \end{pspicture}
  • parallelogram: $A=bh$ , where $b$ is its base and $h$ is its height

    \begin{pspicture}(-1,-2)(6,5) \psline(0,0)(1,4)(5,4)(4,0)(0,0) \rput[b](0,0){.} ... ...(2.3,0.3)(2.3,0) \psline(2,3.7)(2.3,3.7) \psline(2.3,3.7)(2.3,4) \end{pspicture}
  • ellipse: $A=\pi ab$ , where $a$ and $b$ are the major semi-axis and minor semi-axis (not necessarily respectively)

    \begin{pspicture}(0,0)(6,4) \psellipse(3,2)(3,2) \psline(0,2)(6,2) \rput[l](0,2)... ...t[r](2.8,3){$b$} \psline(2.7,2)(2.7,2.3) \psline(2.7,2.3)(3,2.3) \end{pspicture}

Also, in a regular $n$ -gon, each apothem is perpendicular to a side of the polygon. Thus, the formula $\displaystyle A=\frac{1}{2}aP$ , where $a$ is the length of its apothem and $P$ is its perimeter, may be considered as another example.

Any three-dimensional figure has a surface which is two-dimensional. For certain figures, such as cubes and cylinders, this fact can easily be verified by cutting the surface and forcing it to lie flat. The surface area of a three-dimensional figure is the area of its surface.

One method of determining the surface area of any three-dimensional figure is by investigating how much paint would be required to cover its surface with exactly one coat of paint. (This works best if the paint is considered to have no thickness.)

There is another method of determining the surface area of a three-dimensional figure. It works best on figures whose surfaces can easily be cut and forced to lie flat. Once this is done, the surface area can be obtained by determining the area of the resulting two-dimensional figure.

For example, a cube is made up of six congruent squares. If each square has a side of length $s$ , then the surface area of the cube is $6s^2$ .


\begin{pspicture}(-1,-1)(15,7) \psline(2,1.5)(0,1.5)(0,3.5)(1.6,4.2)(3.6,4.2)(3.... ...6.2){$s$} \rput[r](14.3,3){$s$} \rput[b](9,-0.5){flattened cube} \end{pspicture}

As another example, for a cylinder with radius $r$ and height $h$ , its top and bottom, which are circles, can be cut off, and the remaining portion can be unrolled as a rectangle. The radius of each circle is $r$ , so they each have area of $\pi r^2$ . The rectangle has a width that is equal to the circumference of the circular faces, and its height is $h$ . Thus, the area of the rectangle is $2\pi rh$ . Therefore, the surface area of the cylinder is $2\pi r^2+2 \pi rh$ .


\begin{pspicture}(-1,0)(15,11) \psline(0,4)(0,8) \psline(3,4)(3,8) \psellipse(1.... ...,9.7){$r$} \rput[a](7,11){.} \rput[b](7,0.5){flattened cylinder} \end{pspicture}

For some three-dimensional figures, determining its surface area in this manner may not be very straightforward. For example, to determine the surface area of a sphere, one could try peeling an orange and making the portions of orange peel lie flat, but it would be very difficult to come up with the correct formula of $4\pi r^2$ from this procedure. The method of painting as described earlier works much better for spheres.

Remarks

  • When the shape of the geometric figure is complicated, the area can be computed using techniques from calculus. The idea is to break up the geometric figure into tiny squares. The area of the figure may be approximated by the total area occupied by these squares. The interesting thing is whether it is possible to get an exact answer if the squares are tiny enough. For all of the examples given above, using the tiny squares will give the exact answer.
  • The concept of area is a special case of a general concept called measure, or more appropriately, product measure.




"area" is owned by Wkbj79. [ full author list (2) ]
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See Also: area of a polygonal region, developable surface, area of plane region, volume, length, base and height of triangle

Also defines:  surface area
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Cross-references: product measure, measure, Calculus, sphere, faces, circumference, rectangle, circles, radius, cylinders, cubes, surface, polygon, side, apothem, major semi-axis, parallelogram, triangle, perpendicular, line segments, lengths, Euclidean geometry, cover, squares, contained
There are 141 references to this entry.

This is version 33 of area, born on 2007-04-20, modified 2009-03-20.
Object id is 9230, canonical name is Area2.
Accessed 8219 times total.

Classification:
AMS MSC51-00 (Geometry :: General reference works )
 51M25 (Geometry :: Real and complex geometry :: Length, area and volume)

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elementary definition of area by Wkbj79 on 2007-04-20 18:41:23
Due to a response that I sent Mathprof regarding a correction that he filed, I decided to add this entry. This is my humble attempt to try to define/describe area from an elementary (precalculus) point of view. I realize that some people may want to add to or change this entry, so I will leave that option open for a while. Since I want this entry to be from an elementary point of view though, I would greatly appreciate it if derivations from calculus (or beyond) are left out of this entry. On the other hand, links to entries that deal with concepts from calculus or beyond are welcome, so long as they relate to the entry. For example, I used the word "cover", which links to the topology definition, but I feel that this link is appropriate.

I would highly encourage people to add entries that show, at least in a special case, that the elementary concept of area corresponds to the concept of area as presented in calculus. I may file this as a request at some point.
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