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[parent] compact Hausdorff space is extremally disconnected if its function algebra is a bounded complete lattice (Theorem)

Let $X$ be a compact Hausdorff space and $C(X)$ the algebra of continuous functions $X \longrightarrow \mathbb{C}$ . Recall that $C(X)$ is a vector lattice with the usual order: $f\leq g \Longleftrightarrow g-f$ takes positive (or zero) values.

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Theorem - If every subset of $C(X)$ that is bounded from above has a least upper bound (i.e. $C(X)$ is a bounded complete lattice), then $X$ is extremally disconnected.




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Other names:  sufficient condition for a compact Hausdorf space to be extremally disconnected

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Cross-references: extremally disconnected, lattice, bounded complete, least upper bound, bounded from above, subset, theorem, positive, vector lattice, continuous functions, algebra, Hausdorff space, compact

This is version 2 of compact Hausdorff space is extremally disconnected if its function algebra is a bounded complete lattice, born on 2008-03-06, modified 2008-03-06.
Object id is 10368, canonical name is CompactHausdorffSpaceIsExtremallyDisconnectedIfItsFunctionAlgebraIsABoundedCompleteLattice.
Accessed 797 times total.

Classification:
AMS MSC06F20 (Order, lattices, ordered algebraic structures :: Ordered structures :: Ordered abelian groups, Riesz groups, ordered linear spaces)
 46J10 (Functional analysis :: Commutative Banach algebras and commutative topological algebras :: Banach algebras of continuous functions, function algebras)
 54G05 (General topology :: Peculiar spaces :: Extremally disconnected spaces, $F$-spaces, etc.)

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