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[parent] finite ring has no proper overrings (Result)

The regular elements of a finite commutative ring $R$ are the units of the ring (see the parent of this entry). Generally, the largest overring of $R$ , the total ring of fractions $T$ , is obtained by forming $S^{-1}R$ , the extension by localization, using as the multiplicative set $S$ the set of all regular elements, which in this case is the unit group of $R$ . The ring $R$ may be considered as a subring of $T$ , which consists formally of the fractions $\frac{a}{s} = as^{-1}$ with $a\in R$ and $s\in S$ . Since every $s$ has its own group inverse $s^{-1}$ in $S$ and so in $R$ , it's evident that $T$ contains no other elements than the elements of $R$ . Consequently, $T = R$ , and therefore also any overring of $R$ coincides with $R$ .

Accordingly, one can not extend a finite commutative ring by using a localization. Possible extensions must be made via some kind of adjunction. A more known special case is a finite integral domain -- it is always a field and thus closed under the divisions.




"finite ring has no proper overrings" is owned by pahio.
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See Also: extension by localization, classical ring of quotients, a finite integral domain is a field, ring adjunction, formal power series

Keywords:  regular element, unit

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Cross-references: divisions, closed under, field, extensions, localization, elements, group inverse, fractions, subring, unit group, multiplicative set, extension by localization, total ring of fractions, overring, ring, units, commutative ring, finite, regular elements

This is version 7 of finite ring has no proper overrings, born on 2005-04-11, modified 2005-04-22.
Object id is 6942, canonical name is FiniteRingHasNoProperOverrings.
Accessed 1731 times total.

Classification:
AMS MSC13G05 (Commutative rings and algebras :: Integral domains)

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