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[parent] pointwise limit of bounded operators is bounded (Corollary)

The following result is a corollary of the principle of uniform boundedness.

Theorem - Let $X$ be a Banach space and $Y$ a normed vector space. Let $(T_n) \in B(X,Y)$ be a sequence of bounded operators from $X$ to $Y$ . If $(T_nx)$ converges for every $x \in X$ , then the operator

$T:X \longrightarrow Y$

$\displaystyle Tx = \lim_{n \rightarrow \infty} T_n x $
is linear and bounded. Moreover, the sequence $(\|T_n\|)$ is bounded.

Proof : It is clear that the operator $T$ is linear.

For each $x \in X$ we have $\displaystyle \;\sup_n \|T_nx\| < \infty\;$ since $(T_nx)$ is convergent. By the principle of uniform boundedness we must also have $\displaystyle M := \sup_n \|T_n\| < \infty$ .

Then for each $x \in X$ we have

$\displaystyle \Vert Tx\Vert = \lim_{n \rightarrow \infty} \Vert T_nx\Vert \leq M\Vert x\Vert $

which means that $T$ is bounded. $\square$




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Cross-references: clear, proof, operator, converges, bounded operators, sequence, normed vector space, Banach space, theorem, Principle of Uniform Boundedness

This is version 1 of pointwise limit of bounded operators is bounded, born on 2007-09-13.
Object id is 9933, canonical name is PointwiseLimitOfBoundedOperatorsIsBounded.
Accessed 1016 times total.

Classification:
AMS MSC46B99 (Functional analysis :: Normed linear spaces and Banach spaces; Banach lattices :: Miscellaneous)
 47A05 (Operator theory :: General theory of linear operators :: General )

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