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[parent] quadratic imaginary norm-Euclidean number fields (Theorem)

Theorem 1. The imaginary quadratic fields $\mathbb{Q}(\sqrt{d})$ with $d = -1,\,-2,\,-3,\,-7,\,-11$ are norm-Euclidean number fields.

Proof. $1^\circ.$ $d \not\equiv 1\;(\mbox{mod}\;4)$ , i.e. $d = -1$ or $d = -2$ . Any element $\gamma$ of the field $\mathbb{Q}(\sqrt{d})$ has the canonic form $\gamma = c_0+c_1\sqrt{d}$ where $c_0,\,c_1\in\mathbb{Q}$ . We may write $\gamma = (p+r)+(q+s)\sqrt{d}$ , where $p$ is the rational integer nearest to $c_0$ and $q$ the one nearest to $c_1$ . So $|r| \le \frac{1}{2}$ , $|s| \le \frac{1}{2}$ . Thus we may write $$\gamma = \underbrace{(p+q\sqrt{d})}_\varkappa+ \underbrace{(r+s\sqrt{d})}_\delta,$$ where $\varkappa$ is an integer of the field. We then can estimate $$0 \le \mbox{N}(\delta) = (r+s\sqrt{d})(r-s\sqrt{d}) = r^2-s^2d = r^2+s^2|d| \le \left(\frac{1}{2}\right)^2\!+2\left(\frac{1}{2}\right)^2 = \frac{3}{4} < 1,$$ and therefore $|\mbox{N}(\delta)| < 1$ . According to the theorem 1 in the parent entry, $\mathbb{Q}(\sqrt{-1})$ and $\mathbb{Q}(\sqrt{-2})$ are norm-Euclidean number fields.

$2^\circ.$ $d \equiv 1\;(\mbox{mod}\;4)$ , i.e. $d\in\{-3,\,-7,\,-11\}$ . The algebraic integers of $\mathbb{Q}(\sqrt{d})$ have now the canonic form $\frac{a+b\sqrt{d}}{2}$ with $2\,|\,a\!-\!b$ . Let $\gamma = c_0+c_1\sqrt{d}$ where $c_0,\,c_1\in\mathbb{Q}$ be an arbitrary element of the field. Choose the rational integer $q$ such that $\frac{q}{2}$ is as close to $c_1$ as possible, i.e. $c_1 = \frac{q}{2}+s$ with $|s| \le \frac{1}{4}$ , and the rational integer $t$ such that $\frac{q}{2}+t$ is as close to $c_0$ as possible; then $c_0 = \frac{q+2t}{2}+r = \frac{p}{2}+r$ with $|r| \le \frac{1}{2}$ . Then we can write $$\gamma = \frac{p}{2}+r+(\frac{q}{2}+s)\sqrt{d} = \underbrace{\frac{p+q\sqrt{d}}{2}}_\varkappa+ \underbrace{(r+s\sqrt{d})}_\delta.$$ The number $\varkappa$ is an integer of the field, since $p-q = 2t \equiv 0\,\,(\mbox{mod}\,2)$ . We get the estimation $$0 \le \mbox{N}(\delta) = r^2+s^2|d| \le \left(\frac{1}{2}\right)^2\!+11\left(\frac{1}{4}\right)^2 = \frac{15}{16} < 1,$$ so $|\mbox{N}(\delta)| < 1$ . Thus the fields in question are norm-Euclidean number fields.

Theorem 2. The only quadratic imaginary norm-Euclidean number fields $\mathbb{Q}(\sqrt{d})$ are the ones in which $d = -1,\,-2,\,-3,\,-7,\,-11$ .

Proof. Let $d$ be any other negative (square-free) rational integer than the above mentioned ones.

$1^\circ.$ $d \not\equiv 1\;(\mbox{mod}\;4)$ . The integers of $\mathbb{Q}(\sqrt{d})$ are $a+b\sqrt{d}$ where $a,\,b\in\mathbb{Z}$ . We show that there is a number $\gamma$ that can not be expressed in the form $\gamma = \varkappa+\delta$ with $\varkappa$ an integer of the field and $|\mbox{N}(\delta)| < 1$ . Assume that $\gamma := \frac{1}{2}\sqrt{d} = \varkappa+\delta$ where $\varkappa = a+b\sqrt{d}$ is an integer of the field ($a,\,b\in\mathbb{Z}$ ). Then $\delta = \gamma-\varkappa = -a+(\frac{1}{2}-b)\sqrt{d}$ and $\mbox{N}(\delta) = |a|^2+|d|\cdot|\frac{1}{2}-b|^2$ . Because $b$ cannot be 0, we have $|\frac{1}{2}-b| \ge \frac{1}{2}$ and thus $$|\mbox{N}(\delta)| \ge 0+|d|\left(\frac{1}{2}\right)^2 = \frac{|d|}{4}\ge \frac{5}{4} > 1.$$ Therefore $\mathbb{Q}(\sqrt{d})$ can not be a norm-Euclidean number field ($d = -5,\,-6,\,-10$ and so on).

$2^\circ.$ $d \equiv 1\;(\mbox{mod}\;4)$ . Now $|d| \ge 15$ . The integers of $\mathbb{Q}(\sqrt{d})$ have the form $\varkappa = \frac{a+b\sqrt{d}}{2}$ with $2\,|\,a-b$ . Suppose that $\gamma = \frac{1}{4}+\frac{1}{4}\sqrt{d} = \varkappa+\delta$ . Then $\delta = \gamma-\varkappa = (\frac{1}{4}-\frac{a}{2})+ (\frac{1}{4}-\frac{b}{2})\sqrt{d}$ and $$|\mbox{N}(\delta)| \ge \left|\frac{1}{4}-\frac{a}{2}\right|^2+|d|\cdot\left|\frac{1}{4}-\frac{b}{2}\right|^2 \ge \left(\frac{1}{4}\right)^2\!+15\left(\frac{1}{4}\right)^2 = 1.$$ So also these fields $\mathbb{Q}(\sqrt{d})$ are not norm-Euclidean number fields.

Remark. The rings of integers of the imaginary quadratic fields of the above theorems are thus PID's. There are, in addition, four other imaginary quadratic fields which are not norm-Euclidean but anyway their rings of integers are PID's (see lemma for imaginary quadratic fields, class numbers of imaginary quadratic fields, unique factorization and ideals in ring of integers, divisor theory).




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See Also: norm-Euclidean number field, imaginary quadratic field, class numbers of imaginary quadratic fields

Other names:  imaginary quadratic Euclidean number fields, imaginary Euclidean quadratic fields
Keywords:  imaginary quadratic field

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Cross-references: divisor theory, unique factorization and ideals in ring of integers, class numbers of imaginary quadratic fields, lemma for imaginary quadratic fields, norm-Euclidean, addition, PID's, rings of integers, square-free, negative, number, algebraic integers, rational integer, field, proof, norm-Euclidean number fields, imaginary quadratic fields, theorem

This is version 10 of quadratic imaginary norm-Euclidean number fields, born on 2007-03-28, modified 2008-10-29.
Object id is 9126, canonical name is QuadraticImaginaryEuclideanNumberFields.
Accessed 2205 times total.

Classification:
AMS MSC11R04 (Number theory :: Algebraic number theory: global fields :: Algebraic numbers; rings of algebraic integers)
 11R21 (Number theory :: Algebraic number theory: global fields :: Other number fields)
 13F07 (Commutative rings and algebras :: Arithmetic rings and other special rings :: Euclidean rings and generalizations)

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