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stable isomorphism
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(Definition)
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Let $R$ be a ring with unity 1. Two left $R$ -modules $M$ and $N$ are said to be stably isomorphic if there exists a finitely generated free $R$ -module $R^n$ ($n\geq1$ ) such that $$M\oplus R^n\cong N\oplus R^n.$$ A left $R$ -module is said to be stably free if it is stably isomorphic to a finitely generated free $R$ -module. In other words, $M$ is stably free if $$M\oplus R^m\cong R^n$$ for some positive integers $m,n$ .
Remark In the Grothendieck group $K_0(R)$ of a ring $R$ with 1, two finitely generated projective module representatives $M$ and $N$ such that $[M]=[N]\in K_0(R)$ iff they are stably isomorphic to each other. In particular, $[M]$ is the zero element in $K_0(R)$ iff it is stably free.
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"stable isomorphism" is owned by CWoo.
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(view preamble | get metadata)
Cross-references: zero element, iff, finitely generated projective module, ring, Grothendieck group, integers, positive, finitely generated, ring with unity
This is version 1 of stable isomorphism, born on 2005-02-03.
Object id is 6707, canonical name is StableIsomorphism.
Accessed 2518 times total.
Classification:
| AMS MSC: | 19A13 ($K$-theory :: Grothendieck groups and $K_0$ :: Stability for projective modules) |
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Pending Errata and Addenda
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