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[parent] sufficient condition of identical congruence (Theorem)

Theorem. Let $f(X) := a_nX^n+\ldots+a_1X+a_0$ be a polynomial in $X$ with integer coefficients $a_i$ and $m$ a positive integer. If the congruence

$\displaystyle f(x) \;\equiv\; 0 \pmod{m}$ (1)

is satisfied by $m$ successive integers $x$ , then it is satisfied by all integers $x$ , in other words it is an identical congruence.

Proof. There is an integer $x_0$ such that (1) is satisfied by $$x \;:=\; x_0\!+\!1,\,x_0\!+\!2,\,\ldots,\,x_0\!+\!m.$$ But these values form a complete residue system modulo $m$ . Thus, if $x$ is an arbitrary integer, one has $$x \;\equiv\; x_0\!+\!r \pmod{m} \quad\mbox{where}\;\; 1\leqq r \leqq m.$$ This implies $$a_ix^i \;\equiv\; a_i(x_0\!+\!r)^i \pmod{m} \quad\mbox{for}\;\; i = 0,\,1,\,\ldots,\,n$$ and consequently $$\underbrace{\sum_{i=0}^na_ix^i}_{f(x)} \;\equiv\; \sum_{i=0}^na_i(x_0\!+\!r)^i \;=\; f(x_0\!+\!r) \;\equiv\; 0 \pmod{m}.$$ Accordingly, (1) is true for any integer $x$ , Q.E.D.

Note. Though the congruence (1) is identical, it need not be a question of a formal congruence

$\displaystyle f(X) \;\underline{\equiv}\; 0 \pmod{m},$ (2)

i.e. all coefficients $a_i$ need not be congruent to 0 modulo $m$ .




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See Also: sufficient, congruence of arbitrary degree, formal congruence


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Cross-references: formal congruence, implies, complete residue system, proof, identical congruence, congruence, positive, coefficients, integer, polynomial, theorem

This is version 5 of sufficient condition of identical congruence, born on 2009-05-15, modified 2009-05-16.
Object id is 11788, canonical name is SufficientConditionOfPolynomialCongruence.
Accessed 271 times total.

Classification:
AMS MSC11A07 (Number theory :: Elementary number theory :: Congruences; primitive roots; residue systems)
 11C08 (Number theory :: Polynomials and matrices :: Polynomials)

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