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totally bounded (Definition)

Let $A$ be a subset of a topological vector space $X$ .

$A$ is called totally bounded if , for each neighborhood $G$ of 0, there exists a finite subset $S$ of $A$ with $A$ contained in $S + G$ .

The definition can be restated in the following form when $X$ is a metric space:

A set $A \subseteq X$ is said to be totally bounded if for every $\epsilon>0$ , there exists a finite subset $\{s_1,s_2,\ldots ,s_n\}$ of $A$ such that $A\subseteq \bigcup _{k=1} ^n B(s_k,\epsilon )$ , where $B(s_k,\epsilon)$ denotes the open ball around $s_k$ with radius $\epsilon$ .

Bibliography

1
G. Bachman, L. Narici, Functional analysis, Academic Press, 1966.
2
A. Wilansky, Functional Analysis, Blaisdell Publishing Co., 1964
3
W. Rudin, Functional Analysis, 2nd ed. McGraw-Hill , 1973




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See Also: metric space, bounded, subset

Keywords:  bounded, totally, totally bounded, total, bound, finite bound

Attachments:
totally bounded uniform space (Definition) by CWoo
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Cross-references: radius, open ball, metric space, contained, finite, neighborhood, topological vector space, subset
There are 6 references to this entry.

This is version 8 of totally bounded, born on 2002-11-19, modified 2006-09-04.
Object id is 3608, canonical name is TotallyBounded.
Accessed 7899 times total.

Classification:
AMS MSC54E35 (General topology :: Spaces with richer structures :: Metric spaces, metrizability)

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