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totally bounded
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(Definition)
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Let $A$ be a subset of a topological vector space $X$ .
$A$ is called totally bounded if , for each neighborhood $G$ of 0, there exists a finite subset $S$ of $A$ with $A$ contained in $S + G$ .
The definition can be restated in the following form when $X$ is a metric space:
A set $A \subseteq X$ is said to be totally bounded if for every $\epsilon>0$ , there exists a finite subset $\{s_1,s_2,\ldots ,s_n\}$ of $A$ such that $A\subseteq \bigcup _{k=1} ^n B(s_k,\epsilon )$ , where $B(s_k,\epsilon)$ denotes the open ball around $s_k$ with radius $\epsilon$ .
- 1
- G. Bachman, L. Narici, Functional analysis, Academic Press, 1966.
- 2
- A. Wilansky, Functional Analysis, Blaisdell Publishing Co., 1964
- 3
- W. Rudin, Functional Analysis, 2nd ed. McGraw-Hill , 1973
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"totally bounded" is owned by Mathprof. [ full author list (3) | owner history (4) ]
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Cross-references: radius, open ball, metric space, contained, finite, neighborhood, topological vector space, subset
There are 6 references to this entry.
This is version 8 of totally bounded, born on 2002-11-19, modified 2006-09-04.
Object id is 3608, canonical name is TotallyBounded.
Accessed 7899 times total.
Classification:
| AMS MSC: | 54E35 (General topology :: Spaces with richer structures :: Metric spaces, metrizability) |
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Pending Errata and Addenda
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