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Revision Browser : $\operatorname{ker} L=\{0\}$ if and only if $L$ is injective
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diff 2006-10-27 12:14:54 - revision [ Version 7 --> (current) ] by Mathprof
Changes for correction #10728 ('proof supplied').

diff 2006-10-26 11:02:58 - revision [ Version 6 --> Version 7 ] by Mathprof
Changes for correction #10721 ('remove theorem numbering').

diff 2006-10-26 11:01:48 - revision [ Version 5 --> Version 6 ] by Mathprof
Changes for correction #10722 ('two addenda').

diff 2006-09-13 21:19:21 - revision [ Version 4 --> Version 5 ] by Mathprof
Changes for correction #8981 ('suppress link').

diff 2006-08-02 08:55:14 - revision [ Version 3 --> Version 4 ] by matte

displaying all 5 items.