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Revision difference : group cohomology
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Let $G$ be a group and let $M$ be a (left) $G$-module. The Let $G$ be a group and let $M$ be a (left) $G$-module. The
$0^{th}$ \emph{cohomology group} of the $G$-module $M$ is $0^{th}$ \emph{cohomology group} of the $G$-module $M$ is
$$H^0(G,M)=\{m\in M\colon \forall \sigma \in G,\ \sigma m=m\}$$ $$H^0(G,M)=\{m\in M\colon \forall \sigma \in G,\ \sigma m=m\}$$
which is the set of elements of $M$ which are $G$-invariant, also which is the set of elements of $M$ which are $G$-invariant, also
denoted by $M^G$. denoted by $M^G$.
A map $\phi\colon G\to M$ is said to be a \emph{crossed A map $\phi\colon G\to M$ is said to be a \emph{crossed
homomorphism} (or \emph{1-cocycle}) if homomorphism} (or \emph{1-cocycle}) if
$$\phi(\alpha\beta)=\phi(\alpha)+\alpha\phi(\beta)$$ $$\phi(\alpha\beta)=\phi(\alpha)+\alpha\phi(\beta)$$
for all $\alpha,\beta \in G$. If we fix $m\in M$, the map for all $\alpha,\beta \in G$. If we fix $m\in M$, the map
$\rho\colon G\to M$ defined by $\rho\colon G\to M$ defined by
$$\rho(\alpha)=\alpha m-m$$ $$\rho(\alpha)=\alpha m-m$$
is clearly a crossed homomorphism, said to be \emph{principal} (or is clearly a crossed homomorphism, said to be \emph{principal} (or
\emph{1-coboundary}). We define the following groups: \emph{1-coboundary}). We define the following groups:
\begin{eqnarray} \begin{eqnarray}
\nonumber Z^1(G,M)&=&\{\phi\colon G\to M\colon \phi \text{ is a 1-cocycle}\}\\ \nonumber Z^1(G,M)&=&\{\phi\colon G\to M\colon \phi \text{ is a 1-cocycle}\}\\
\nonumber B^1(G,M)&=&\{\rho\colon G\to M\colon \rho \text{ is a \nonumber B^1(G,M)&=&\{\rho\colon G\to M\colon \rho \text{ is a
1-coboundary}\} 1-coboundary}\}
\end{eqnarray} \end{eqnarray}
Finally, the $1^{st}$ \emph{cohomology group} of the $G$-module Finally, the $1^{st}$ \emph{cohomology group} of the $G$-module
$M$ is defined to be the quotient group: $M$ is defined to be the quotient group:
$$H^1(G,M)=Z^1(G,M)/B^1(G,M)$$ $$H^1(G,M)=Z^1(G,M)/B^1(G,M)$$
Similarly, there are cohomology groups $H^n(G,M)$ for $n>1$ but Similarly, there are cohomology groups $H^n(G,M)$ for $n>1$ but
the first two are the ones which are most frequently found in the the first two are the ones which are most frequently found in the
literature. literature.
The following proposition is very useful when trying to compute The following proposition is very useful when trying to compute
cohomology groups: cohomology groups:
\begin{prop} \begin{prop}
Let $G$ be a group and let $A,B,C$ be $G$-modules related by an Let $G$ be a group and let $A,B,C$ be $G$-modules related by an
exact sequence: exact sequence:
$$0\to A\to B\to C\to 0$$ $$0\to A\to B\to C\to 0$$
Then there is a long exact sequence in cohomology: Then there is a long exact sequence in cohomology:
$$0\to H^0(G,A)\to H^0(G,B)\to H^0(G,C)\to H^1(G,A)\to H^1(G,B)\to $$0\to H^0(G,A)\to H^0(G,B)\to H^0(G,C)\to H^1(G,A)\to H^1(G,B)\to
H^1(G,C)$$ H^1(G,C)$$
\end{prop} \end{prop}
\begin{thebibliography}{9} \begin{thebibliography}{9}
\bibitem{serre} J.P. Serre, {\em Galois Cohomology}, \bibitem{serre} J.P. Serre, {\em Galois Cohomology},
Springer-Verlag, New York. Springer-Verlag, New York.
\bibitem{milne} James Milne, {\em Elliptic Curves}, \PMlinkexternal{online course \bibitem{milne} James Milne, {\em Elliptic Curves}, \PMlinkexternal{online course
notes}{http://www.jmilne.org/math/CourseNotes/math679.html}. notes}{http://www.jmilne.org/math/CourseNotes/math679.html}.
\bibitem{silverman} Joseph H. Silverman, {\em The Arithmetic of Elliptic Curves}. Springer-Verlag, New York, 1986. \bibitem{silverman} Joseph H. Silverman, {\em The Arithmetic of Elliptic Curves}. Springer-Verlag, New York, 1986.
\end{thebibliography} \end{thebibliography}