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Revision difference : Legendre polynomial
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The Legendre polynomials are a set of polynomials $\{P_i\}_{i=0}^{\infty}$ each of order $i$ that satisfy Legendre's ODE: $$\frac{d}{dx}[(1-x)^2 P_n'(x)] + n(n+1)P_n(x) = 0$$. The Legendre polynomials are a set of polynomials $\{P_i\}_{i=0}^{\infty}$ each of order $i$ that satisfy Legendre's ODE: $$\frac{d}{dx}[(1-x)^2 P_n'(x)] + n(n+1)P_n(x) = 0$$.
Alternatively $P_n$ is an eigenfunction of the self-adjoint differential operator $\frac{d}{dx}(1-x)^2 \frac{d}{dx}$ with eigenvalue $-n(n+1)$. Alternatively $P_n$ is an eigenfunction of the self-adjoint differential operator $\frac{d}{dx}(1-x)^2 \frac{d}{dx}$ with eigenvalue $n(n+1)$.
The Legendre polynomials are also known as Legendre Functions of the first kind. The Legendre polynomials are also known as Legendre Functions of the first kind.
By Sturm-Liouville theory, this means they're orthogonal over some interval with By Sturm-Liouville theory, this means they're orthogonal over some interval with
some weight function. In fact it can be shown that, they're orthogonal on $[-1, 1]$ with weight function $W(x) = 1$. As with any set of orthogonal polynomials, this can be used to generate them (up to normalization) by Gramm-Schmidt orthogonalization of the monomials $\{x^i\}$. The normalization used some weight function. In fact it can be shown that, they're orthogonal on $[-1, 1]$ with weight function $W(x) = 1$. As with any set of orthogonal polynomials, this can be used to generate them (up to normalization) by gram-schmidt orthogonalization of the monomials $\{x^i\}$. The normalization used
is $\langle P_n \| P_n \rangle = 2 / (2n + 1)$, which makes $P_n(\pm 1) = (\pm 1)^n$ is $\langle P_n \| P_n \rangle = 2 / (2n + 1)$, which makes $P_n(\pm 1) = (\pm 1)^n$
Rodrigues's Formula (which can be generalized to some other polynomial sets) is a sometimes convenient form of $P_n$ in terms of derivatives: Rodrigues's Formula is a sometimes convenient form of $P_n$ in terms of
derivatives:
$$P_n(x) = \frac{1}{2^n n!} \left( \frac{d}{dx} \right)^n (x^2 - 1)^n$$ $$P_n(x) = \frac{1}{2^n n!} \left( \frac{d}{dx} \right)^n (x^2 - 1)^n$$
The first few explicitly are: The first few explicitly are:
\begin{eqnarray*} \begin{eqnarray*}
P_0(x) &=& 1 \\ P_0(x) &=& 1 \\
P_1(x) &=& x \\ P_1(x) &=& x \\
P_2(x) &=& \frac{1}{2} (3x^2 - 1) \\ P_2(x) &=& \frac{1}{2} (3x^2 - 1) \\
P_3(x) &=& \frac{1}{2} (5x^3 - 3x) \\ P_3(x) &=& \frac{1}{2} (5x^3 - 3x) \\
P_4(x) &=& \frac{1}{8} (35x^4 - 30x^2 + 3) \\ P_4(x) &=& \frac{1}{8} (35x^4 - 30x^2 + 3) \\
... ...
\end{eqnarray*} \end{eqnarray*}
As all orthogonal polynomials do, these satisfy a three-term recurence relation: As all orthogonal polynomials do, these satisfy a three-term recurence relation:
$$(n+1)P_{n+1}(x) = (2n+1)xP_{n}(x) - (n-1)P_{n}(x)$$ $$(n+1)P_{n+1}(x) = (2n+1)xP_{n}(x) - (n-1)P_{n}(x)$$
The Legendre Functions of the second kind also satisfy the Legendre ODE but are not regular at the origin. The Legendre Functions of the second kind also satisfy the Legendre ODE but are not regular at the origin.
Related are the Associated Legendre Functions, and Spherical Harmonics. Related are the Associated Legendre Functions, and Spherical Harmonics.