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Revision difference : additive category
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Let $\mathcal{C}$ be a category. Then $\mathcal{C}$ is an \emph{additive category} if Let $\mathcal{C}$ be a category. Then $\mathcal{C}$ is an \emph{additive category} if
\begin{enumerate} \begin{enumerate}
\item $\mathcal{C}$ is a preadditive category, and \item $\mathcal{C}$ is a preadditive category, and
\item for every pair of objects $A,B$ in $\mathcal{C}$, their \PMlinkname{product}{CategoricalDirectProduct} exists. \item for every pair of objects $A,B$ in $\mathcal{C}$, their \PMlinkname{product}{CategoricalDirectProduct} exists.
\end{enumerate} \end{enumerate}
\textbf{Proposition}. In a preadditive category, coproduct of two objects exists iff their product exists. Furthermore, they are isomorphic. \textbf{Proposition}. In a preadditive category, coproduct of two objects exists iff their product exists. Furthermore, they are isomorphic.
\begin{proof}We shall prove the fact if the product $D$ of objects $A$ and $B$ exists, then $D$ is also their coproduct. The other direction is dual. \begin{proof}We shall prove the fact if the product $D$ of objects $A$ and $B$ exists, then $D$ is also their coproduct. The other direction is dual.
Suppose $D$ is the product of $A$ and $B$, with morphisms Suppose $D$ is the product of $A$ and $B$, with morphisms
$$\xymatrix@1{D\ar[r]^{\pi_A}&A}\qquad\mbox{ and }\qquad\xymatrix@1{D\ar[r]^{\pi_B}&B}.$$ $$\xymatrix@1{D\ar[r]^{\pi_A}&A}\qquad\mbox{ and }\qquad\xymatrix@1{D\ar[r]^{\pi_B}&B}.$$
From these two morphisms, we construct two commutative diagrams From these two morphisms, we construct two commutative diagrams
$$\xymatrix{&A \\ A \ar[ur]^1 \ar[dr]_0 \ar@{-->}[r]^{\alpha} & D $$\xymatrix{&A \\ A \ar[ur]^1 \ar[dr]_0 \ar@{-->}[r]^{\alpha} & D
\ar[u]_{\pi_A} \ar[d]^{\pi_B}\\ &B} \ar[u]_{\pi_A} \ar[d]^{\pi_B}\\ &B}
\qquad\mbox{ and }\qquad \qquad\mbox{ and }\qquad
\xymatrix{&A \\ B \ar[ur]^0 \ar[dr]_1 \ar@{-->}[r]^{\beta} & D \xymatrix{&A \\ B \ar[ur]^0 \ar[dr]_1 \ar@{-->}[r]^{\beta} & D
\ar[u]_{\pi_A} \ar[d]^{\pi_B}\\ &B}$$ \ar[u]_{\pi_A} \ar[d]^{\pi_B}\\ &B}$$
where $0$ and $1$ are zero morphisms and identity morphisms on $A$ and $B$, and $\alpha$ and $\beta$ are morphisms based on the definition of the product $D$. where $0$ and $1$ are zero morphisms and identity morphisms on $A$ and $B$, and $\alpha$ and $\beta$ are morphisms based on the definition of the product $D$.
Then it's not hard to see that $D$ is a coproduct of $A$ and $B$ with morphisms $\alpha$ and $\beta$, for if $r:A\rightarrow C$ and $s:B\rightarrow C$ are two morphisms into an object $C$, we can form two morphisms $r\pi_A$ and $s\pi_B$, both from $D$ to $C$. Since $\operatorname{hom}(D,C)$ is an abelian group, these two can then be added to form $f:=r\pi_A+s\pi_B$. Then $f\alpha=(r\pi_A+s\pi_B)\alpha=r$, and similarly $f\beta=s$. This shows that $D$ is also the coproduct of $A$ and $B$ with morphisms $\alpha$ and $\beta$. Then it's not hard to see that $D$ is a coproduct of $A$ and $B$ with morphisms $\alpha$ and $\beta$, for if $r:A\rightarrow C$ and $s:B\rightarrow C$ are two morphisms into an object $C$, we can form two morphisms $r\pi_A$ and $s\pi_B$, both from $D$ to $C$. Since $\operatorname{hom}(D,C)$ is an abelian group, these two can then be added to form $f:=r\pi_A+s\pi_B$. Then $f\alpha=(r\pi_A+s\pi_B)\alpha=r$, and similarly $f\beta=s$. This shows that $D$ is also the coproduct of $A$ and $B$ with morphisms $\alpha$ and $\beta$.
\end{proof} \end{proof}
An easy way to remember the relationships among the various morphisms in the above proof are the following two matrix products: An easy way to remember the relationships among the various morphisms in the above proof are the following two matrix products:
\begin{center} \begin{center}
$ $
\begin{pmatrix} \begin{pmatrix}
\pi_A \\ \pi_A \\
\pi_B \pi_B
\end{pmatrix} \end{pmatrix}
\begin{pmatrix} \begin{pmatrix}
\alpha & \beta \alpha & \beta
\end{pmatrix} \end{pmatrix}
= =
\begin{pmatrix} \begin{pmatrix}
1 & 0 \\ 1 & 0 \\
0 & 1 0 & 1
\end{pmatrix} \end{pmatrix}
\qquad \qquad
\mbox{ and } \mbox{ and }
\qquad \qquad
\begin{pmatrix} \begin{pmatrix}
r & s r & s
\end{pmatrix} \end{pmatrix}
\begin{pmatrix} \begin{pmatrix}
\pi_A \\ \pi_A \\
\pi_B \pi_B
\end{pmatrix} \end{pmatrix}
=f$. =f$.
\end{center} \end{center}
As a result of the above proposition, in an additive category, finite products and finite coproducts are synonymous. Given objects $A,B$, we denote $A\oplus B$ to be their product. We also call it the \emph{direct sum} of $A$ and $B$. As a result of the above proposition, in an additive category, finite products and finite coproducts are synonymous. Given objects $A,B$, we denote $A\oplus B$ to be their product. We also call it the \emph{direct sum} of $A$ and $B$.
Many preadditive categories are also examples of additive categories. The category $\textbf{CyclGrp}$ of cyclic groups as the subcategory of the category of abelian groups is an example of a preadditive category that is not additive, for the product of two cyclic groups $Z_p$ and $Z_q$ where $p$ and $q$ are not coprime does not exist in $\textbf{CyclGrp}$. Many preadditive categories are also examples of additive categories. The category $\textbf{CyclGrp}$ of cyclic groups as the subcategory of the category of abelian groups is an example of a preadditive category that is not additive, for the product of two cyclic groups $Z_p$ and $Z_q$ where $p$ and $q$ are coprime does not exist in $\textbf{CyclGrp}$.